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2 years ago

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The specific heat capacity of water is 4.184 J/(g.˚C). How much thermal energy is required to change the temperature of 700.0g o

f water from 25.6˚C to 75.4 ˚C?

1 answer:

worty [1.4K]2 years ago

4 0

Answer:

Should be 145854.24J or:

145.9 KJ

Explanation:

I did the calculations

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At an accident scene on a level road, investigators measure a car's skid mark to be 93 m long. It was a rainy day and the coeffi

USPshnik [31]

Answer:

u = 25 m/s

Explanation:

given,

length of skid = 93 m

coefficient of friction = 0.35

final velocity = 0 m/s

initial velocity = ?

force here is friction f = μ mg

F = ma

now com paring

-μ mg = m a

a = - μ g

a = - 0.35 x 9.8

a = -3.43 m/s²

we know,

v² = u² + 2 a s

0 = u² - 2 x 3.43 x 93

u² = 637.98

u = 25.26 m/s

u = 25 m/s (two significant figure)

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3 years ago

How is the Milky Way changing? A. Large numbers of stars are being born inside nebulas. B. The Milky Way does not change. C. Lar

Over [174]

Answer:

D. Large numbers of stars are undergoing blue-shift.

Explanation:

The Milky Way is changing because a large numbers of stars are undergoing blue-shift.

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3 years ago

A string with a mass density of 3 * 10^-3 kg/m is under a tension of 380 N and is fixed at both ends. One of its resonance frequ

Delvig [45]

Answer:

(a) the fundamental frequency of this string is 65 Hz

(b) the harmonics of the given frequencies are third and fourth respectively.

(c) the length of the string is 2.74 m

Explanation:

Given;

mass density of the string, μ = 3 x 10⁻³ kg/m

tension of the string, T = 380 N

resonating frequencies, 195 Hz and 260 N

For the given resonant frequencies;

$195 = \frac{n}{2l} \sqrt{\frac{T}{\mu} } ---(1)\\\\260 = \frac{n+1}{2l} \sqrt{\frac{T}{\mu} } ---(2)\\\\divide \ (2) \ by (1)\\\\\frac{260}{195} = \frac{n+1 }{n} \\\\260n = 195(n+1)\\\\260 n = 195 n + 195\\\\260n - 195n = 195\\\\65n = 195\\\\n = \frac{195}{65} \\\\n = 3$

(c) From any of the equations, solve for Length of the string (L);

$195 = \frac{n}{2l} \sqrt{\frac{T}{\mu} } \\\\195 = \frac{3}{2l}\sqrt{\frac{380}{3\times 10^{-3}} } \\\\l = \frac{3}{2\times 195}\sqrt{\frac{380}{3\times 10^{-3}} }\\\\l = 2.74 \ m$

(a) the fundamental frequency is calculated as;

$f_o = \frac{1}{2l} \sqrt{\frac{T}{\mu} } \\\\f_o = \frac{1}{2\times 2.74} \sqrt{\frac{380}{3\times 10^{-3} } }\\\\f_o = 65 \ Hz$

(b) harmonics of the given frequencies;

the first harmonic (n = 1) = f₀ = 65 Hz

the second harmonic (n = 2) = 2f₀ = 130 Hz

the third harmonic (n = 3) = 3f₀ = 195 Hz

the fourth harmonic (n = 4) = 4f₀ = 260 Hz

Thus, the harmonics of the given frequencies are third and fourth respectively.

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2 years ago

What is the ultimate source of energy that makes the Sun shine?

zavuch27 [327]

Answer:

The sun's energy comes from thermonuclear fusion reactions.

Explanation:

Due to the Sun's strong gravitational pull, hydrogen atoms fuse, resulting in helium atoms. During this process, tremendous amounts of energy are released, or the energy of the Sun.

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3 years ago

Which of the following measurements has two significant digits?

myrzilka [38]

0.022 has 2 digits because you would count from the left starting with the first nonzero number

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3 years ago

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