Answer:
B.0
Step-by-step explanation:
4-2x2+2/2-1
4-4+1-1
0+0
0
X = first child
x +2 = 2nd child
x+ 4 = 3rd child
It doesn't matter if the ages are odd or even - there is two years between each child in age.
The sum would be
x + x + 2 + x + 4 or 3x + 6.
Lets try it with a sample age. Let's say the youngest is 5 middle is 7 and oldest is 9
The sum of their ages is 21 (5 + 7 + 9)
Using our answer of 3x + 6 where x is the age of the youngest child, we get
3(5) +6 which is also 21.
This could also be solved by having x represent the middle age child
x-2 is the youngest (2 years less than the middle)
x = the middle
x+2 is the oldest (2 years older than the middle)
The sum of these would be x-2 + x + x +2 or simply 3x (the 2's cancel out)
Since the middle child is 7 3x would mean 3 (7)=21
You could also set this up using x for the oldest child
x= oldest
x-2= middle
x-4= youngest (The sum of this is 3x - 6)
3 (9) -6 is also 21.
Answer:
Translation
Step-by-step explanation:
You just move the shape down
Solution
Here 10th term =35
Rule = Add 3 to get the previous term to get the next term.
This is an Arithmetic sequence, where the common difference (d) = 3
Let's take the first term = a
2nd term = a + d
3rd term = a + 2d
4th term = a + 3d
and so on.
10th term = a + 9d
The 10th term is 35. So 35 = a + 9(3) [d = 3]
Now let's find the value of a (first term)
35 = a + 27
a= 35 - 27
a = 8
We have to find the 5th term.
5th term = a + 4d
5th term = 8 + 4*3 = 8 +12 = 20
Answer: 20.
Thank you. :)