All categories

3 years ago

Number of molecules of water in 6 moles

1 answer:

5 0

I mol of anything is 6.02 * 10^23 (in this case molecules of water)
6 mols of water = x

1/6 = 6.02 * 10^23 / x Cross multiply
x = 6 * 6.02* 10^23
x = 3.612 * 10^24 molecules in 6 mols of water

You might be interested in

blank is the energy required for a chemical reaction to take place, and blank is the energy associated with every substance.

Korolek [52]

Heat is the first one...and the secound one is kinetic

5 0

3 years ago

Read 2 more answers

What is the value of the equilibrium constant for this redox reaction?

aivan3 [116]

Correct answer: Option D, K = 5.04 × 10^52

Reason:
We know that,
Ecell = $\frac{0.0592}{n}log(K)$ ,
where n = number of electrons = 2 (in present case)
K = equilibrium constant.

Also, Ecell = +1.56 v

Therefore, 1.56 = $\frac{0.0592}{2}log(K)$
Therefore, log (K) = 52.703
Therefore, K = 5.04 X 10^52

8 0

3 years ago

Read 2 more answers

The equilibrium constant, Kc, for the following reaction is 56.0 at 278 K. 2CH2Cl2(g) CH4(g) + CCl4(g) When a sufficiently large

BabaBlast [244]

Answer:

21.5 M

Explanation:

1) Equilibrium equation (given):

2CH₂Cl₂ (g) ⇄ CH₄ (g) + CCl₄ (g)

2) Write the concentration changes when some concentration, A, of CH₂Cl₂ (g) sample is introduced into an evacuated (empty) vessel:

2CH₂Cl₂ (g) ⇄ CH₄ (g) + CCl₄ (g)

A - x x x

3) Replace x with the known (found) equilibrium concentraion of CCl₄ (g) of 0.348 M

2CH₂Cl₂ (g) ⇄ CH₄ (g) + CCl₄ (g)

A - 0.3485 0.348 0.348

4) Write the equilibrium constant equation, replace the known values and solve for the unknown (A):

Kc = [ CH₄ (g) ] [ CCl₄ (g) ] / [ CH₂Cl₂ (g) ]²

56.0 = 0.348² / A²

A² = 56.0 / 0.348² = 462.

A = 21.5 M ← answer

7 0

3 years ago

How many moles of glucose does 1.2 x 10^24 molecules represent

sammy [17]

<h3>Answer:</h3>

2.0 mol C₆H₁₂O₆

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

1.2 × 10²⁴ molecules C₆H₁₂O₆ (glucose)

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

Set up: $\displaystyle 1.2 \cdot 10^{24} \ molecules \ C_6H_{12}O_6(\frac{1 \ mol \ C_6H_{12}O_6}{6.022 \cdot 10^{23} \ molecules \ C_6H_{12}O_6})$
Divide: $\displaystyle 1.99269 \ mol \ C_6H_{12}O_6$

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

1.99269 mol C₆H₁₂O₆ ≈ 2.0 mol C₆H₁₂O₆

3 0

3 years ago

When I2 and FeCl2 are mixed together, iodine (I) cannot replace chlorine (Cl) in the compound because iodine is lower on the per

Nata [24]

Answer: The given statement is true.

Explanation: If this reaction would have occurred, then this reaction would be considered as displacement reaction.

Displacement reactions are the reaction in which more reactive element displaces the less reactive element in a chemical reaction. This is based on the reactivity of elements.

Reactivity of elements is the tendency of the elements to gain or loose electrons. The reactivity decreases down the group in a periodic table.

In the given reaction, Iodine and chlorine are the elements of the same group in the periodic table and iodine lies below chlorine in the group. So, the reactivity of iodine is less than the reactivity of chlorine.

Hence, in the given reaction, iodine will not replace chlorine because it lies below in the periodic table.

$FeCl_2+I_2\rightarrow \text{No reaction}$

3 0

3 years ago