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victus00 [196]
3 years ago
11

A magnetic B field of strength 0.4 T is perpendicular to a loop with an area of 1 m2. If the area of the loop is reduced to zero

in 0.7 s, then what is the magnitude of the induced emf voltage?
Physics
1 answer:
Norma-Jean [14]3 years ago
3 0

Answer:

The magnitude of the induced e.m.f is 571 mV

Explanation:

Given;

magnetic field strength, B = 0.4T

area of the loop, A = 1m²

time = 0.7s

Since the angle of inclination of the magnetic field, then the direction of the induced e.m.f, θ = 0

According to faraday's law; the induced emf is directly proportional to the rate of change of flux.

Thus, magnitude of the induced e.m.f is given as

E.M.F = \frac{\delta \phi}{\delta t} \\\\\phi = BAcos \theta =  BAcos0 = BA\\\\E.M.F = \frac{0.4 X1}{0.7} = 0.571 V

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What is the ground-state electron configuration of a neutral atom of titanium?
Georgia [21]

Answer:

\bold {1s^22s^22p^63s^23p^64s^23d^2}

Explanation:

electronic configuration of an atom is the spatial arrangement of the electrons around the nucleus in the energy orbits

We know that the atomic number of Titanium is 22

The electronic configuration of Titanium is

1s^22s^22p^63s^23p^64s^23d^2

3 0
3 years ago
During its lifespan, what characteristics of the sun will change
4vir4ik [10]
During its lifepsan, the sun's core would keep contracting and heating up.

The temperature will keep increasing to the point where the temperature outside the core will get to hydrogen fusion temperatures.
The sun will grow in surface and eventually became the Red Giant
6 0
3 years ago
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Four objects are situated along the y axis as follows: a 1.99-kg object is at 2.99 m, a 2.96-kg object is at 2.57 m, a 2.43-kg o
Dominik [7]

Answer:

The center of mass for the object is  y_c = 1.063 \  m from the origin

Explanation:

From the question we are told that

   The mass of the first object is  m_1 =  1.99 \  kg

   The position of first object with respect to origin y_1 =  2.99 \ m

   The mass of the second object is  m_2 =  2.96 \  kg

   The position of second object with respect to origin y_2 =  2.57 \ m

   The mass of the third object is  m_3 =  2.43  \  kg

   The position of third object with respect to origin y_3 =  0 \ m

   The mass of the fourth object is  m_3 =  3.96  \  kg

   The position of fourth object with respect to origin y_3 =  -0.502  \ m

Generally the center of mass of the object along the x-axis is  zero  because all the mass lie on the y axis

Generally the location of the center mass of the object is mathematically represented as

    y_c = \frac{m_1 * y_1 + m_2 * y_2 + m_3 * y_3 + m_4 * y_4}{m_1 + m_2 + m_3 + m_4}

=>y_c = \frac{1.99 * 2.99 + 2.96 * 2.57 + 2.43 * 0 + 3.96 * (-0.502)}{1.99+ 2.96  + 2.43 + 3.96}

=>y_c = 1.063 \  m

3 0
3 years ago
A stone with a weight of 5.29 N is launched vertically from ground level with an initial speed of 26.0 m/s, and the air drag on
makkiz [27]

Answer:

a) 19.4 m/s

b) 19 m/s

Explanation:

a) In the given question,

the potential energy at the initial point = Ui = 0

the potential energy at the final point = Uf = mgh

the kinetic energy at the initial point = Ki = 1/2 mv₀².

the kinetic energy at the final point = Kf = 0

work done by air= Ea= fh =  0.262 N

Now, using the law of conservation of energy

initial energy= final energy

Ki +Ui = Kf + Uf +Ea

1/2 mv₀² + 0 = 0 + mgh + fh

1/2 mv₀² = mgh + fh

h = v₀²/ 2g (1 +f/w)

calculate m

m= w/g = 5.29 /9.8

= 0.54 kg

h = 20 ²/ (2 x9.80) x (1 0.265/5.29)

h = 19.4 m.

b) 1/2 mv² + 2fh = 1/2 mv₀²

Vg = 19 m/s

6 0
3 years ago
A harmonic wave is traveling along a rope. It is observed that the oscillator that generates the wave completes 37.0 vibrations
Goryan [66]

Answer:

0.47 m

Explanation:

N = Number of vibrations = 37

t = total time taken = 33 s

T = time period of each vibration

frequency of vibration is given as

f = \frac{N}{t} \\f = \frac{37}{33} \\f = 1.12 Hz

d = distance traveled along the rope = 421 cm = 4.21 m

t = time taken to travel the distance = 8 s

v = speed of the wave

Speed of the wave is given as

v = \frac{d}{t}\\v = \frac{4.21}{8}\\v = 0.53 ms^{-1}

\lambda = wavelength of the harmonic wave

wavelength of the harmonic wave is given as

\lambda = \frac{v}{f} \\\lambda = \frac{0.53}{1.12} \\\lambda = 0.47 m

8 0
2 years ago
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