Answer:
The magnitude of the induced e.m.f is 571 mV
Explanation:
Given;
magnetic field strength, B = 0.4T
area of the loop, A = 1m²
time = 0.7s
Since the angle of inclination of the magnetic field, then the direction of the induced e.m.f, θ = 0
According to faraday's law; the induced emf is directly proportional to the rate of change of flux.
Thus, magnitude of the induced e.m.f is given as
Answer:
200 C
Explanation:
Let C1 and C2 be their charges. According to Coulomb's law
where k = is the constant, R = 0.4m is the distance between them, F = 120 N is their resulting charge force
Since their total charge is 200C:
or
We can substitute the above equation
or
So the larger charge is C = 200 C
We have the equation of motion , where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.
Here s = 300 m, u = 0 m/s, a = 9.81
Substituting
Now we have v = u+at, where v is the final velocity
Here u = 0 m/s, a= 9.81 and t = 7.82 seconds
Substituting
v = 0+9.8*7.82 = 76.68 m/s
The speed with which the penny strikes the ground = 76.68 m/s.