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victus00 [196]
3 years ago
11

A magnetic B field of strength 0.4 T is perpendicular to a loop with an area of 1 m2. If the area of the loop is reduced to zero

in 0.7 s, then what is the magnitude of the induced emf voltage?
Physics
1 answer:
Norma-Jean [14]3 years ago
3 0

Answer:

The magnitude of the induced e.m.f is 571 mV

Explanation:

Given;

magnetic field strength, B = 0.4T

area of the loop, A = 1m²

time = 0.7s

Since the angle of inclination of the magnetic field, then the direction of the induced e.m.f, θ = 0

According to faraday's law; the induced emf is directly proportional to the rate of change of flux.

Thus, magnitude of the induced e.m.f is given as

E.M.F = \frac{\delta \phi}{\delta t} \\\\\phi = BAcos \theta =  BAcos0 = BA\\\\E.M.F = \frac{0.4 X1}{0.7} = 0.571 V

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A body travel according to the law x(t)=2t+3t3 calculate the accelaration of body at t=2s
faust18 [17]

Answer:

28m/s

Explanation:

Given law,

⇒ x(t) = 2t + 3t³

Where, t = 2s

Then,

⇒ x(2) = 2(2) + 3(2)³

⇒ 4 + 3(8)

⇒ 4 + 24

⇒ 28 m/s

Acceleration is 28m/s

4 0
3 years ago
A crane is used to lower weights into a lake for an underwater construction project. Determine the tension in the cable of the c
atroni [7]

Answer:

Tension in the cable = 591292.8 N or 591.3 kN

Explanation:

Tension in the cable = Weight of object in air - upthrust/bouyancy due to the liquid

Weight of object in air = mass * acceleration due to gravity, g

Since mass is not given, it is obtained from the formula, mass = density * volume

Volume of the sphere = 4/3πr³ where r, radius = 2 m; π = 22/7

volume = 4/3 * 22/7 * (2m)³

volume of sphere = 33.52 m³

Density of concrete sphere = specific gravity * density of water

where, specific gravity = 2.8, density of water = 1000 kg/m³

density of concrete =  2.8 * 1000 kg/m³

density of concrete = 2800 kg/m³

acceleration due to gravity, g = 9.8 m/s²

Thus, weight of concrete = 2800 kg/m³ * 33.52 m³ * 9.8 m/s² = 919788.8 N

Upthrust = density of water * volume of sphere * g

Upthrust = 1000 kg/m³ * 33.52 m³ * 9.8 m/s² = 328496 N

The tension in the cable is the calculated as below;

Tension in the cable = Weight of object in air - upthrust/bouyancy due to the liquid

Tension in cable = 919788.8 N - 328.496 N = 591292.8 N

Therefore, tension in the cable is 591292.8 N or 591.3 kN

5 0
3 years ago
Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.5
Marat540 [252]

Answer:

Option C

Explanation:

From the question we are told that:

Mass m=0.015kg

Radius r=0.5m

Time t=0.70

Generally the equation for Tension is mathematically given by

 T=\frac{4mr}{t^2} \pi

 T=\frac{4*0.015*0.5}{(0.70)^2} (3.142)

 T=0.60N

Therefore

T=0.60 N, toward the center of the circle

Option C

3 0
3 years ago
A ball is hurled straight up at a speed of 15 m/s, leaving the hand of the thrower 2.00 m above the ground. Compute the times an
SVETLANKA909090 [29]

Answer:

5.37 m/s

0.98 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times -9.81\times 10+15^2}\\\Rightarrow v=5.37\ m/s

Velocity of the ball when it passes an observer sitting at a window is 5.37 m/s

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{5.37-15}{-9.81}\\\Rightarrow t=0.98\ s

Time taken by the ball to pass the observer sitting at a window is 0.98 seconds

3 0
3 years ago
I need all the answers to all of them today cause I have to give it in tomorrow
k0ka [10]
1. Volume
2. liquid
3. Gas
4. Kinetic energy?
5.Gas
6 0
3 years ago
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