What is the first wave in the electromagnetic spectrum?
1 answer:
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Answer:
3.59 m/s
Explanation:
The average velocity is defined as:
The turtle first walks 18m south, and then is taken 1,1Km (or 1100m) north. Thus, the total displacement is 1082m north (1100m north - 18m south).
Now we have to calculate the total time, which will be equal to the sum of the time the turtle walked and the time it was taken by truck.
The walking time is 3.5 minutes. Since 1 minute = 60 seconds, then the walking time is 210 seconds.
To calculate the truck time we use the equation:
Time =
Where the distance the truck travelled is 1100m and the speed of the truck is 12m/s.
Thus,
Truck time= = 91.67s
The total time is the sum of the walking time and the truck time.
Total time = 210s + 91.67s = 301.67s.
As mencioned previously, the average velocity is equal to total displacement/ total time, thus:
Average velocity = = 3.59 m/s North
Since the average velocity is a vector, it has a magnitude and a direction. In this case the magnitude is 3.59 m/s and the direction is north since the turtle's final displacement is north of where it started.
Answer:
Velocity, v = 0.239 m/s
Explanation:
Given that,
The distance between two consecutive nodes of a standing wave is 20.9 cm = 0.209 m
The hand generating the pulses moves up and down through a complete cycle 2.57 times every 4.47 s.
For a standing wave, the distance between two consecutive nodes is equal to half of the wavelength.
Frequency is number of cycles per unit time.
Now we can find the velocity of the wave.
Velocity = frequency × wavelength
v = 0.574 × 0.418
v = 0.239 m/s
So, the velocity of the wave is 0.239 m/s.
Explanation:
We have,
Speed of plane a is 900 km/h
Plane b is moving at a rate of
It is required to find which plane is faster. To find which plane is faster, we need to compare their speeds.
Speed of a plane a is 900 km/h and that of plane b is 50 km/h. So, we can say that plane a is moving faster.