Answer:
(a). The height of the cliff is 41.67 m.
(b). The maximum height of the ball is 41.67 m
(c). The ball's impact speed is 16.52 m/s.
Explanation:
Given that,
Speed = 33 m/s
Angle = 60°
Time = 3.0 sec
(a). We need to calculate the height of the cliff
Using equation of motion


Put the value into the formula


(b). We need to calculate the maximum height of the ball
Using formula of height

Put the value into the formula


(c). We need to calculate the vertical component of velocity of ball
Using equation of motion


Put the value into the formula


We need to calculate the horizontal component of velocity of ball
Using formula of velocity

Put the value into the formula


We need to calculate the ball's impact speed
Using formula of velocity

Put the value into the formula


Hence, (a). The height of the cliff is 41.67 m.
(b). The maximum height of the ball is 41.67 m
(c). The ball's impact speed is 16.52 m/s.