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crimeas [40]
2 years ago
13

Which best describes what occurs when an object takes in a wave as the wave hits it?.

Physics
1 answer:
statuscvo [17]2 years ago
7 0

Answer:

Absorption

Explanation:

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How much current is in a circult that includes a 9.0-volt battery and a bulb with a resistance of 4.0 ohms?
SVETLANKA909090 [29]

Answer:

Current, I = 2.3 A

Explanation:

We have,

Voltage of the battery in a circuit is 9 volts

Resistance of the circuit is 4 ohms

It is required to find the current in a circuit. When the voltage and the resistance of the circuit is given then we can find the current in it is given by Ohm's law as :

V=IR

I is electric current

I=\dfrac{V}{R}\\\\I=\dfrac{9}{4}\\\\I=2.25\ A

or

I = 2.3 A

So, the current in the circuit is 2.3 A.

6 0
3 years ago
Grade 11 question paper or memo for 2015
denis-greek [22]
What your saying doesn't make sense.
5 0
3 years ago
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What type of stress can cause an anticline?<br><br> A. Compression<br><br> B. force<br><br> C. shear
Andrei [34K]
The stress that can cause on the anticline , is the Compression 
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3 years ago
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The escape speed from the moon is much smaller than from earth. True or False
Lisa [10]

Answer:

True

The escape speed from the Moon is much smaller than from Earth.

Explanation:

The escape speed is defined as:

v_{e} = \sqrt{\frac{2GM}{r}}  (1)

Where G is the gravitational constant, M is the mass and r is the radius.

The mass of the Earth is 5.972x10^{24}kg and its radius is 6371000m

Then, replacing those values in equation 1 it is gotten.

v_{e} = \sqrt{\frac{(2)(6.67x10^{-11}N.m^{2}/kg^{2})(5.972x10^{24}kg)}{(6371000m)}}  

v_{e} = 11.18m/s

For the case of the Moon:

v_{e} = \sqrt{\frac{(2)(6.67x10^{-11}N.m^{2}/kg^{2})(7.347x10^{22}Kg)}{(1737000m)}}  

v_{e} = 2.38m/s

Hence, the escape speed from the Moon is much smaller than from Earth.

Since it has a smaller mass and smaller radius compared to that from the Earth.

4 0
3 years ago
A violin with string length 32 cm and string density 1.5 g/cm resonates in its fundamental with the first overtone of a 2.0-m or
love history [14]

Answer:

T=1022.42 N

Explanation:

Given that

l = 32 cm ,μ = 1.5 g/cm

L =2 m  ,V= 344 m/s

The pipe is closed so n= 3 ,for first over tone

f=\dfrac{nV}{4L}

f=\dfrac{3\times 344}{4\times 2}

f= 129 Hz

The tension in the string given as

T = f²(4l²) μ

Now by putting the values

T = f²(4l²) μ

T = 129² x (4 x 0.32²)  x 1.5 x  10⁻³ x 100

T=1022.42 N

6 0
3 years ago
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