Answer:
α=0.625rad/s^2
v=340m/s
w=10rad/s
θ=320rad
Explanation:
Constant angular acceleration = ∆w/∆t
angular acceleration = 20/32
α=0.625rad/s^2
Linear velocity v=wr
v = 20×17= 340m/s
Average angular velocity
w0+w1/2
w= 0+20/2
w= 20/2
w=10rad/s
What angle did it rotate with
θ=wt
θ= 10×32
=320rad
Answer:
The final temperature is T2= 5.35°C
Explanation:
Apply the Gay-lussacs's law we have

P1, initial pressure= 5.00 x 10^6 Pa
T1, initiation temperature= 25.°C
P2, final pressure= 1.07 x 10^6 Pa
T2, final temperature= ?

Cross multiplying and making T2 subject of formula we have

T2= 5.35°C
Answer:

Explanation:
The impulse-momentum theorem states the impulse on an object is equal to the change in momentum of that object. Momentum is given by
. Since mass is constant, the train's change in momentum is:
(two significant figures).
Impulse is also given as
, where
is the average force applied and
is change in time. Since
is given as
, we have the following equation:
(two significant figures).