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3 years ago

Movement of a stationary object (2words)

Physics

1 answer:

Whitepunk [10]3 years ago

6 0

Induced motion or movement

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A light ray incident from medium 1 to medium 2, where n1>n2. When the incident angle exceed the critical angle ac, the refrac

vovikov84 [41]

Explanation:

(a)

Critical angle is the angle at the angle of refraction is 90°. After the critical angle, no refraction takes place.

Using Snell's law as:

$n_1\times {sin\theta_i}={n_2}\times{sin\theta_r}$

Where,

${\theta_i}$ is the angle of incidence

${\theta_r}$ is the angle of refraction = 90°

${n_2}$ is the refractive index of the refraction medium

${n_1}$ is the refractive index of the incidence medium

Thus,

$n_1\times {sin\ \theta_{critical}}={n_2}\times{sin\ 90^0}$

The formula for the calculation of critical angle is:

${sin\theta_{critical}}=\frac {n_2}{n_1}$

Where,

${\theta_{critical}}$ is the critical angle

(b)

No it cannot occur. It only occur when the light ray bends away from the normal which means that when it travels from denser to rarer medium.

7 0

4 years ago

Kim designed an experiment to show how heat can be transferred from one place to another. The steps of the experiment are shown

Radda [10]

Heat transfer by conduction, since kim is trying to show that heat travels from one end of the rod to the other. This is nothing but conduction

3 0

3 years ago

Charged particles q1=− 4.80 nC and q2=+ 4.80 nC are separated by distance 3.00 mm , forming an electric dipole. The charges are

Dafna1 [17]

Answer:

Electric field, E = 936.19 N/C

Explanation:

It is given that,

Charge 1, $q_1=-4.8\ nC=-4.8\times 10^{-9}\ C$

Charge 2, $q_2=+4.8\ nC=+4.8\times 10^{-9}\ C$

Distance between them, d = 3 mm = 0.003 m

Torque, $\tau=8\times 10^{-9}\ N-m$

Angle between electric field and line connecting the charge, $\theta=36.4^{\circ}$

We need to find the torque exerted on the dipole. The torque experienced by the dipole in the electric field is given by :

$\tau=pE\ sin\theta$

p is the dipole moment, $p=qd$

$\tau=qdE\ sin\theta$

$E=\dfrac{\tau}{qd\ sin\theta}$

$E=\dfrac{8\times 10^{-9}}{4.8\times 10^{-9}\times 0.003\ sin(36.4)}$

E = 936.19 N/C

So, the magnitude of electric field on the dipole is 936.19 N/C. Hence, this is the required solution.

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3 years ago

What is oscillating to form a light wave?

aniked [119]

I think the answer is B ( matter )

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4 years ago

Which exoplanet has the most Earth-like orbit?

Digiron [165]

Answer: Kepler-452b

I think

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3 years ago