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max2010maxim [7]
2 years ago
12

You have a two-liter sample of each of the following gases, all at 25 °C and one atmosphere pressure. Which sample will weigh th

e most?A) Ammonia.B) Argon.C) Carbon dioxide.D) Nitrogen dioxide.E) Oxygen.
Chemistry
1 answer:
stepladder [879]2 years ago
4 0

Answer: D) Nitrogen Dioxide

Explanation:

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Ca(OH)2 + H3PO4 = Ca3(PO4)2 + H2O
larisa [96]
Make a quick chart with each element represented, and count them up. HINT - leave the polyatomic anions together - in this case, PO4

Left      Right
1     Ca  3
2      O   1
5      H   2
1    PO4 2

Begin by balancing like finding common denominators of fractions - apply to both sides:
I started by adding a 2 in front of H3PO4 on the left, them 6 in front of H2O on the right. Last, a 3 in front of Ca (OH)2. Then, re-count using the chart format to make sure you're right.

3Ca(OH)2 + 2H3PO4 = Ca3(PO4)2 + 6H2O

4 0
3 years ago
Hypothesis II: Write the equation with Iron (III) Chloride and balance it: Iron + Copper (II) chloride --> Iron (III) chlorid
stich3 [128]

Answer:

Fe + CuCl2 = FeCl2 + Cu

Explanation:

This is already balanced.

5 0
3 years ago
How many grams of CaCl2 are in 250 mL of 2.0 M CaCl2?
Tom [10]
The answer is:  " 56 g CaCl₂ " .
__________________________________________________________

Explanation:
__________________________________________________________
2.0 M CaCl₂  = 2.0 mol CaCl₂ / L  ; 

Since: "M" = "Molarity" (measurement of concentration); 

                  = moles of solute per L {"Liter"} of solution.
__________________________________________________________
Note the exact conversion:  1000 mL = 1 L . 

Given: 250 mL ;   

250 mL = ?  L  ?  ;  


250 mL * (1 L / 1000 L) =  (250/1000) L = 0.25 L . 
___________________________________________________________
 
(2.0 mol CaCl₂ / L ) * (0.25L) = (2.0) * (0.25) mol  = 0.50 mol CaCl₂ ;

We have: 0.50 mol CaCl₂ ;  Convert to "g" (grams):

→ 0.50 mol CaCl₂  .
___________________________________________________________
1 mol CaCl₂ = ? g ?

From the Periodic Table of Elements:

1 mol Ca = 40.08 g

1 mol Cl  =  <span>35.45 g .
</span>
There are 2 atoms of Cl in " CaCl₂ " ;  

→ Note the subscript, "2", in the " Cl₂ " ; 
__________________________________________________________
So, to calculate the molar mass of "CaCl₂" :

40.08 g  +  2(35.45 g) = 

40.08 g  +  70.90 g = 110.98 g ;  round to 4 significant figures; 

                                 → round to 111 g/mol .
__________________________________________________________
So:

→  0.50 mol CaCl₂  = ? g CaCl₂  ? ; 

→  0.50 mol CaCl₂ * (111 g CaCl₂ / mol CaCl₂) ;

                                             = (0.50) * (111 g) CaCl₂ ;

                                             =  55.5 g CaCl₂  ;

                                                → round to 2 significant figures; 

                                                →  56 g CaCl₂ .
___________________________________________________________
The answer is:  " 56 g CaCl₂ " .
___________________________________________________________
6 0
3 years ago
Read 2 more answers
How many moles of H2SO4 are needed to prepare 200 mL of a 1.0 M solution?
jok3333 [9.3K]
The answer is 0.2moles
4 0
3 years ago
A) How many grams of water are produced when 2.50 g of aluminum
egoroff_w [7]
The correct answer is 13 I just did it bro
5 0
3 years ago
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