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Sever21 [200]
2 years ago
5

A sample of magnesium is burned in oxygen to form magnesium oxide. What mass of oxygen is consumed if 74.62 g magnesium oxide is

formed from 45.00 g magnesium
Chemistry
1 answer:
lana [24]2 years ago
3 0
74.62 g of magnesium oxide is formed from 45.00 g magnesium so 74.62-45.00= 29.62 g of oxygen is consumed or in other words a new compound is formed in the burning of magnesium in oxygen with a heavier mass than the pure magnesium.
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What are two processes that result in rocks being broken down into smaller pieces !?
Snowcat [4.5K]
<span>"Chemical weathering and physical weathering" would be the correct answer

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3 years ago
How do cells use lipids and carbohydrates?
Nata [24]

Answer:

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8 0
3 years ago
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Suppose you have a mixture of copper sulfate (CuSO4) and azulene (C10H8, you may wish to know the structure of azulene). Both co
iVinArrow [24]

Answer:

Aqueous layer (1 M HCI)

Explanation:

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3 0
3 years ago
It takes 495.0 kJ of energy to remove 1 mole of electron from an atom on the surface of sodium metal. How much energy does it ta
Zigmanuir [339]

Answer:

\lambda=241.9\ nm

Explanation:

The work function of the sodium= 495.0 kJ/mol

It means that  

1 mole of electrons can be removed by applying of 495.0 kJ of energy.

Also,  

1 mole = 6.023\times 10^{23}\ electrons

So,  

6.023\times 10^{23} electrons can be removed by applying of 495.0 kJ of energy.

1 electron can be removed by applying of \frac {495.0}{6.023\times 10^{23}}\ kJ of energy.

Energy required = 82.18\times 10^{-23}\ kJ

Also,  

1 kJ = 1000 J

So,  

Energy required = 82.18\times 10^{-20}\ J

Also, E=\frac {h\times c}{\lambda}

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

So,  

79.78\times 10^{-20}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{\lambda}

\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{82.18\times 10^{-20}}

\lambda=\frac{10^{-26}\times \:19.878}{10^{-20}\times \:82.18}

\lambda=\frac{19.878}{10^6\times \:82.18}

\lambda=2.4188\times 10^{-7}\ m

Also,  

1 m = 10⁻⁹ nm

So,  

\lambda=241.9\ nm

6 0
3 years ago
Anyone have any idea what to do
ra1l [238]

Answer:

2Al+3Fe ------- Al2O3+3Fe

this is answer no 2

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this is answer no 3

I think helps

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4 0
2 years ago
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