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DIA [1.3K]
3 years ago
12

LW Hydraulic engineers in the United States often use, as a unit of volume of water, the acre-foot, defined as the volume of wat

er that will cover 1 acre of land to a depth of 1 ft. A severe thunderstorm dumped 2.0 in. of rain in 30 min on a town of area 26 km2. What volume of water, in acre-feet, fell on the town?
Physics
1 answer:
ruslelena [56]3 years ago
4 0

Answer:

volume of water is 1066.50 acre feet

Explanation:

given data

dia = 2 in = 0.166 feet

area = 26 km² = 26 × 247.105 acre = 6424.73 acre

to find out

volume of water

solution

we know volume of water is express as

volume = area × dia     ....................1

put here value in equation 1

volume = 6424.73 acre × 0.166 feet

volume = 1066.50

so volume of water is 1066.50 acre feet

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What is the correct order of organization from smallest to largest?
Novay_Z [31]

Answer:

D

Explanation:

Cells are the smallest unit of organizaiton, followed by tissues, organs, organ systems, and then organisms themselves.

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3 years ago
A thermally insulated vessel containing a gas whose molar mass is equal to M and the ratio of specific heats cP /cV = γ moves wi
Vika [28.1K]

Answer:

∆T = Mv^2Y/2Cp

Explanation:

Formula for Kinetic energy of the vessel = 1/2mv^2

Increase in internal energy Δu = nCVΔT

where n is the number of moles of the gas in vessel.

When the vessel is to stop suddenly, its kinetic energy will be used to increase the temperature of the gas

We say

1/2mv^2 = ∆u

1/2mv^2 = nCv∆T

Since n = m/M

1/2mv^2 = mCv∆T/M

Making ∆T subject of the formula we have

∆T = Mv^2/2Cv

Multiple the RHS by Cp/Cp

∆T = Mv^2/2Cv *Cp/Cp

Since Y = Cp/CV

∆T = Mv^2Y/2Cp k

Since CV = R/Y - 1

We could also have

∆T = Mv^2(Y - 1)/2R k

6 0
3 years ago
The scientific method can easily be misinterpreted as ___________. Question 1 options: a great magical trick, or slide of hands,
evablogger [386]

Answer:

I think the answer is  

a "cookbook" recipe for performing scientific investigations

Explanation:

5 0
3 years ago
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A 65.0-Ω resistor is connected to the terminals of a battery whose emf is 12.0 V and whose internal resistance is 0.5 Ω. Calcula
Luda [366]

Answer:

a) 0.1832 A

b) 11.91 Volts

c) 2.18 Watt , 0.0168 Watt

Explanation:

(a)

R = external resistor connected to the terminals of the battery = 65 Ω

E = Emf of the battery = 12.0 Volts

r = internal resistance of the battery = 0.5 Ω

i = current flowing in the circuit

Using ohm's law

E = i (R + r)

12 = i (65 + 0.5)

i = 0.1832 A

(b)

Terminal voltage is given as

V_{ab} = i R

V_{ab} = (0.1832) (65)

V_{ab} = 11.91 Volts

(c)

Power dissipated in the resister R is given as

P_{R} = i²R

P_{R} = (0.1832)²(65)

P_{R} = 2.18 Watt

Power dissipated in the internal resistance is given as

P_{r} = i²r

P_{r} = (0.1832)²(0.5)

P_{r} = 0.0168 Watt

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3 years ago
Why you so sussy bakugou?
ruslelena [56]

Answer:

IM CRYIFNNNAEWJN

Explanation:

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