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Romashka [77]
3 years ago
9

Refer to Explorations in Literature for a complete version of this story. How does Lizabeth interact with Miss Lottie in "Marigo

lds"?
A) Lizabeth is intrigued by Miss Lottie and her marigolds, so she enjoys going by Miss Lottie's house to see her garden.
B) Lizabeth thinks Miss Lottie and her marigolds are strange, and her frustration with her own life drives Lizabeth to destroy the woman's flowers.
C) Lizabeth knows that Miss Lottie doesn't like to be bothered, but she encourages the other children to tease the woman.
D) Lizabeth is afraid of Miss Lottie because she thinks the old woman is a witch, so she avoids her house.
Physics
2 answers:
Artemon [7]3 years ago
8 0

The answer is: B) Lizabeth thinks Miss Lottie and her marigolds are strange, and her frustration with her own life drives Lizabeth to destroy the woman's flowers.

Lizbeth was depicted as an immature character that hates her condiiton and the place where she lived in. When she saw Miss Lottie taking care of the marigold flower, she could not understand why these poor woman had enough passion to take care of the wild flowers despite the horrid situations that she had and not miserable like her. This led her to destroy the flowers.

ivanzaharov [21]3 years ago
7 0
Its B , Lizabeth thinks Miss Lottie and her marigolds are strange, and her frustration with her own life drives Lizabeth to destroy the women's flowers.

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Hence, DNA is coiled into chromosomes in a cell's Nucleus.

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3 years ago
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A body 'A' of mass 1.5kg travelling along the positive X-axis with speed of 4.5m/s collides with another body 'B' of mass 3.2kg,
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Suppose the gas resulting from the sublimation of 1.00 g carbon dioxide is collected over water at 25.0◦c into a 1.00 l containe
AlexFokin [52]

Answer:

0.56 atm

Explanation:

First of all, we need to find the number of moles of the gas.

We know that

m = 1.00 g is the mass of the gas

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So, the number of moles of the gas is

n=\frac{m}{M_m}=\frac{1.00 g}{44.0 g/mol}=0.023 mol

Now we can find the pressure of the gas by using the ideal gas equation:

pV=nRT

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V=1.00 L = 0.001 m^3 is the volume

n = 0.023 mol is the number of moles

R=8.314 J/mol K is the gas constant

T=25.0^{\circ}+273=298 K is the temperature of the gas

Solving the equation for p, we find

p=\frac{nRT}{V}=\frac{(0.023 mol)(8.314 J/mol K)(298 K)}{0.001 m^3}=5.7 \cdot 10^4 Pa

And since we have

1 atm = 1.01\cdot 10^5 Pa

the pressure in atmospheres is

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3 years ago
At t = 0 the components of a radio-controlled car's velocity are vx = 0.5 m/s and vy = 1.2 m/s. Find the components of the car's
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Answer:

x-component of velocity = 5.7 m/s

y-component of velocity = -1.4 m/s          

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Use first equation of motion to find components of velocity at a given time:

v = u + at

where, v is  the final velocity, u is the initial velocity, a is the acceleration and t is the time.

Given:

u_x= 0.5 m/s\\u_y=1.2 m/s\\a_x=2 m/s^2\\a_y=-1m/s^2\\t = (2.6-0)s =2.6 s

v_x=u_x+a_xt\\\Rightarrow v_x=0.5+2\times 2.6\\\Rightarrow v_x=5.7 m/s

v_y=u_y+a_yt\\\Rightarrow v_y=1.2-1\times 2.6\\\Rightarrow v_y=-1.4 m/s

5 0
3 years ago
A parallel-plate capacitor with plates of area 360 cm2 is charged to a potential difference V and is then disconnected from the
Softa [21]

Answer:

Q=3.9825\times 10^{-9} C

Explanation:

We are given that a parallel- plate capacitor is charged to a potential difference V and then disconnected from the voltage source.

1 m =100 cm

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\Delta d=0.8 cm=0.008 m

\Delta V=100 V

We have to find the charge Q on the positive plates of the capacitor.

V=Initial voltage between plates

d=Initial distance between plates

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V=\frac{Q}{C}

Potential difference between plates after moving

V=\frac{Q}{C_1}

V+\Delta V=\frac{Q}{C_1}

\frac{Qd}{\epsilon_0S}+100=\frac{Q(d+\Delta d)}{\epsilon_0S}

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\frac{Q\Delta d}{\epsilon_0 S}=100

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Q=\frac{100\times 8.85\times 10^{-12}\times 0.036}{0.008}

Q=3.9825\times 10^{-9} C

Hence, the charge on positive plate of capacitor=Q=3.9825\times 10^{-9} C

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3 years ago
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