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Romashka [77]
3 years ago
9

Refer to Explorations in Literature for a complete version of this story. How does Lizabeth interact with Miss Lottie in "Marigo

lds"?
A) Lizabeth is intrigued by Miss Lottie and her marigolds, so she enjoys going by Miss Lottie's house to see her garden.
B) Lizabeth thinks Miss Lottie and her marigolds are strange, and her frustration with her own life drives Lizabeth to destroy the woman's flowers.
C) Lizabeth knows that Miss Lottie doesn't like to be bothered, but she encourages the other children to tease the woman.
D) Lizabeth is afraid of Miss Lottie because she thinks the old woman is a witch, so she avoids her house.
Physics
2 answers:
Artemon [7]3 years ago
8 0

The answer is: B) Lizabeth thinks Miss Lottie and her marigolds are strange, and her frustration with her own life drives Lizabeth to destroy the woman's flowers.

Lizbeth was depicted as an immature character that hates her condiiton and the place where she lived in. When she saw Miss Lottie taking care of the marigold flower, she could not understand why these poor woman had enough passion to take care of the wild flowers despite the horrid situations that she had and not miserable like her. This led her to destroy the flowers.

ivanzaharov [21]3 years ago
7 0
Its B , Lizabeth thinks Miss Lottie and her marigolds are strange, and her frustration with her own life drives Lizabeth to destroy the women's flowers.

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A cylinder contains 3.0 L of oxygen at 310 K and 2.5 atm. The gas is heated, causing a piston in the cylinder to move outward. T
Alex_Xolod [135]

Answer:

The gas pressure is: 1.55 atm.

Explanation:

We need to use the equation that relate the variables given at the exercise (pressure, temperature and volume) from the ideal gas law formula, when the mass is constant we can reduce the expretion PV=nRT to \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2} } solving to P2 we get:\frac{P_{1}V_{1}T_{2}}{T_{1}V_{2}}=P_{2} replace the values P_{2}=\frac{2.5*3*610}{9.5*310} =1.55(atm).

5 0
2 years ago
a generator uses loops of area 0.239 m^2, rotating 373 rad/s in a 0.0639 t magnetic field. how many loops must the coil have to
Kaylis [27]

The loops must the coil have to generate a maximum emf of 2500 will be 439.

<h3 /><h3>What is the faraday law of electromagnetic induction?</h3>

According to  Faraday's law of electromagnetic induction, the rate of change of magnetic flux linked with the coil is responsible for generating emf in the coil resulting in the flow of amount of current.

Given data;

Area,A = 0.239 m²

Angular velocity,ω=373 rad/sec

Magnetic field,B=0.0639 T

Maximum emf,E= 2500V

The formula for the maximum induced voltage is;

E{max} = N ×  B × A × ω

2500 = N × 0.639 × 0.0239 × 373

N = 438.66

N = 439 \ turns

Hence, loops must the coil have to generate a maximum emf of 2500  will be 439.

To learn more about the faraday law of electromagnetic induction refer to;

brainly.com/question/26334813

#SPJ1

6 0
2 years ago
18°C = _____ <br> A -255 K<br> B- 0 K<br> C- 18 K<br> D- 291 K
mariarad [96]

Answer:

291 K is the answer

Explanation:

to get Kelvin from Celsius use the following

Kelvin = Celsius +273

= 18 +273

= 291

7 0
2 years ago
You exert 500 N of force down on the earth as you jump into the air. How much force does the earth exert back on you?
zalisa [80]
The same 500N, is the Newton’s Third Law.
6 0
2 years ago
A toy rocket is fired vertically into the air from the ground at an initial velocity of 80 feet per second. Find the time it wil
miskamm [114]

Answer: 16.3 seconds

Explanation: Given that the

Initial velocity U = 80 ft/s

Let's first calculate the maximum height reached by using third equation of motion.

V^2 = U^2 - 2gH

Where V = final velocity and H = maximum height.

Since the toy is moving against the gravity, g will be negative.

At maximum height, V = 0

0 = 80^2 - 2 × 9.81 × H

6400 = 19.62H

H = 6400/19.62

H = 326.2

Let's us second equation of motion to find time.

H = Ut - 1/2gt^2

Let assume that the ball is dropped from the maximum height. Then,

U = 0. The equation will be reduced to

H = 1/2gt^2

326.2 = 1/2 × 9.81 × t^2

326.2 = 4.905t^2

t^2 = 326.2/4.905

t = sqrt( 66.5 )

t = 8.15 seconds

The time it will take for the rocket to return to ground level will be 2t.

That is, 2 × 8.15 = 16.3 seconds

8 0
3 years ago
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