To find the density of any sample, you need to know the Mass (grams), and its Volume (measured in mL or cm³). Divide the mass by the volume in order to get a sample's Density.
Density (P)= Mass(m)/Volume(V)
P=m/V
P=245.8grams/94ml
<span>P=2.65grams per ml </span>
The choices are:
<span>A. The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 0</span>°<span>C.
B. The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 298 K.
C. The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 273</span>°<span> C.
D. The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 100</span>°<span> C.
The correct answer is A because the two gases will have the same temperature and 273 K = 0</span>°C
The reaction is:
Cl2 + 2 KBr --> 2 KCl + Br2
Moles of KCl is
n = m /M = 12 /74 = 0.16 mol
As, twice the moles of KCl is producing from 1 mol of chlorine
mole of Cl2 = 0.16 /2 = 0.08 mol
Mass of Cl2
m /70 = 0.08 = 5.6 g
Hence, 5.6 g mol Cl2 consumed to produce KCl
A volatile acid is an acid that can leave solution and enter the atmosphere.
Covalent bond , hopefully this help :) explanation : .....
