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3 years ago

What type of bond does hydrogen and carbon form

Chemistry

2 answers:

laila [671]3 years ago

7 0

Covalent bond , hopefully this help :) explanation : .....

den301095 [7]3 years ago

6 0

Covalent bond
The carbon-hydrogen bond (C–H bond) is a bond between carbon and hydrogen atoms that can be found in many organic compounds. This bond is a covalent bond meaning that carbon shares its outer valence electrons with up to four hydrogens. This completes both of their outer shells making them stable.

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A distance of one centimeter is the same as ?

rodikova [14]

C because its meters right

4 0

3 years ago

When an ionic compound such as sodium chloride (NaCl) is placed in water, the component atoms of the NaCl crystal dissociate int

sesenic [268]

Answer:

The solution expected to contain the greatest number of solute particles is: A) 1 L of 1.0 M NaCl

Explanation:

The number of particles is calculated as:

a) For Ionic compounds:

molarity × volume in liters × number of ions per unit formula.

b) For covalent compounds:

molarity × volume in liters

The difference is a factor which is the number of particles resulting from the dissociation or ionization of one mole of the ionic compound.

So, calling M the molarity, you can write:

# of particles = M × liters × factor

This table show the calculations for the four solutions from the list of choices:

Compound kind Particles in solution Molarity # of particles

(dissociation) (M) in 1 liter

A) NaCl ionic ions Na⁺ and Cl⁻ 1.0 1.0 × 1 × 2 = 2

B) NaCl ionic ions Na⁺ anc Cl⁻ 0.5 0.5 × 1 × 2 = 1

C) Glucose covalent molecules 0.5 0.5 × 1 × 1 = 0.5

D) Glucose covalent molecules 1.0 1.0 × 1 × 1 = 1

Therefore, the rank in increasing number of particles is for the list of solutions given is: C < B = D < A, which means that the solution expected to contain the greatest number of solute particles is the solution A) 1 L of 1.0 M NaCl.

8 0

3 years ago

Be sure to answer all parts. Hydrogen iodide decomposes according to the reaction 2 HI(g) ⇌ H2(g) + I2(g) A sealed 1.50−L contai

Zarrin [17]

Answer : The concentration of $HI$ and $I_2$ at equilibrium is, 0.0158 M and 0.00302 M respectively.

Explanation :

First we have to calculate the concentration of $H_2, I_2\text{ and }HI$

$\text{Concentration of }H_2=\frac{\text{Moles of }H_2}{\text{Volume of solution}}=\frac{0.00623mol}{1.50L}=0.00415M$

$\text{Concentration of }I_2=\frac{\text{Moles of }I_2}{\text{Volume of solution}}=\frac{0.00414mol}{1.50L}=0.00276M$

$\text{Concentration of }HI=\frac{\text{Moles of }HI}{\text{Volume of solution}}=\frac{0.0244mol}{1.50L}=0.0163M$

Now we have to calculate the value of equilibrium constant (K).

The given chemical reaction is:

$2HI(g)\rightleftharpoons H_2(g)+I_2(g)$

Initial conc. 0.0163 0.00415 0.00276

At eqm. (0.0163-2x) (0.00415+x) (0.00276+x)

As we are given:

Concentration of $H_2$ at equilibrium = 0.00467 M

That means,

(0.00415+x) = 0.00467

x = 0.00026 M

Concentration of $HI$ at equilibrium = (0.0163-2x) = (0.0163-2(0.00026)) = 0.0158 M

Concentration of $I_2$ at equilibrium = (0.00276+x) = (0.00276+0.00026) = 0.00302 M

8 0

3 years ago

In which shell duplet rule is applied, why?

Natasha2012 [34]

Answer:

In first shell duplet rule is applied because first shell contains maximum 2 electrons

Explanation:

5 0

3 years ago

Consider the aldol-dehydration reaction. Draw the two possible products of the reaction between benzaldehyde and methylethylketo

Dafna1 [17]

Solution :

An $\text{aldol condensation}$ reaction is a type of $\text{condensation reaction}$ in organic chemistry where the enol or an enolate ion reacts with the carbonyl compound and forms a $\beta$ -hydroxyaldehyde or a $\beta$ -hydroxyketone, and then followed by a dehydration to give conjugated enone.

Benzaldehyde reacts with methylketone and forms two products:

5 0

3 years ago