Use the portion of the periodic table shown below to answer the questions. A portion of the first three columns of the periodic
table is shown. Column one from top to bottom reads 11 sodium 22.990, 19 potassium 39.098, and 37 rubidium 85.468. Column two reads 12 magnesium 24.305, 20 calcium 40.078, and 38 strontium 87.62. Column three reads 21 scandium 44.956 and 39 yttrium 88.906. Part 1: Name two elements that have the same properties as sodium (Na). (2 points) Part 2: Determine the number of protons, electrons, and neutrons present in an atom of calcium (Ca). Explain how you determined your answer using complete sentences. (6 points)
2 answers:
Answer:
Part 1: Potassium (K), and Rubidium (Rb).
Part 2: Calcium (Ca) has 20 protons and 20 electrons
Explanation:
Part 1: Elements in a same column share a great deal of propreties, in this list Potassium (K), and Rubidium (Rb) are the elements that lies in the same column as Sodium (Na).
Part 2: Calcium (Ca) has 20 protons and 20 electrons. The First information is given by the periodic table, because it is organized in a way that it shows atomic number (proton number) and atomic mass and sometimes some more information about the elements. Atoms are eletricaly neutral, so there must exist 20 electrons within Calcium's orbitals to compensate its 20 protons.
A portion of a periodic table is attached.
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Answer : The pH of the solution is, 2.67
Explanation :
The equilibrium chemical reaction is:
Initial conc. 0.450 0 0
At eqm. (0.450-x) x x
As we are given:
The expression for equilibrium constant is:
Now put all the given values in this expression, we get:
The concentration of = x = 0.00212 M
Now we have to calculate the pH of solution.
Therefore, the pH of the solution is, 2.67
Answer:
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
Next, we identify the limiting reactant by computing the available moles of ethane and the moles of ethane consumed by 60.0 grams of oxygen:
Thus, we notice there are less available moles, for that reason, the ethane is the limiting reactant. Finally, we can compute the produced moles of water by:
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