If the change in kinetic energy of a tennis ball hit by the racket

The current supplied by a battery as a function of time is I(t) = (0.88 A) e^(-t*6 hr). What is the total number of electrons tr

Degger [83]

Answer:

e. 1.2 x 10²³

Explanation:

According to the problem, The current equation is given by:

$I(t)=0.88e^{-t/6\times3600s}$

Here time is in seconds.

Consider at t=0 s the current starts to flow due to battery and the current stops when the time t tends to infinite.

The relation between current and number of charge carriers is:

$q=\int\limits {I} \, dt$

Here the limits of integration is from 0 to infinite. So,

$q=\int\limits {0.88e^{-t/6\times3600s}}\, dt$

$q=0.88\times(-6\times3600)(0-1)$

q = 1.90 x 10⁴ C

Consider N be the total number of charge carriers. So,

q = N e

Here e is electronic charge and its value is 1.69 x 10⁻¹⁹ C.

N = q/e

Substitute the suitable values in the above equation.

$N= \frac{1.9\times10^{4} }{1.69\times10^{-19}}$

N = 1.2 x 10²³

8 0

3 years ago

Phosphorus bursts into flame when exposed to oxygen. What element might be used when storing pure phosphorus to keep it from rea

bekas [8.4K]

<h3><u>Answer;</u></h3>

Argon

<h3><u>Explanation;</u></h3>

Phosphorus is an element found in group 15 of the periodic table, it is one of the element that belongs to nitrogen family.
The element phosphorus exhibits allotrophy, namely; white phosphorus, red phosphorus and black phosphorus.
<u>Phosphorus, particularly the white phosphorus combines with oxygen so easily that it catches fire automatically. Thus, as a safety precaution, white phosphorus is stored under water in laboratories. </u>
<u>It may be also stored in argon, since argon is an inert element which belongs to the noble gases group.</u>

4 0

3 years ago

Read 2 more answers

What is the magnitude of electric field at apoint 2 meter from a point charge q= 4nc

rjkz [21]

I do not have a clue i need to answer so i can ask questions sorry

8 0

3 years ago

Plz help me and HAPPY NEW YEAR ♧

Elena L [17]

Answer:

it's answer is Compound chemical energy

hope it helps you

4 0

2 years ago

It requires 0.30 kJ of work to fully drive a stake into the ground. If the average resistive force on the stake by the ground is

LenaWriter [7]

Answer:

Length of the stake will be 0.3623 m

Explanation:

We have given energy required to fully drive a stake into ground = 0.30 KJ = 300 J

Average resistive force acting on the floor is equal to F = 828 N

We have to find the length of the stake

We know that work done is given by

W = Fd, here W is work done , F is average force and d is the length of the stake

So 300 = 828×d

d = 0.3623 m

So length of the stake will be 0.3623 m

6 0

3 years ago