We know, s = ut + 1/2gt²
In free-fall, u = 0
so, t = √2s/g
Now, substitute the values,
t = √2*4 / 9.8 [ -ve sign shows opposite direction only ]
t = √8/ 9.8
t = 0.90 sec
In short, Your Answer would be 0.90 sec
Hope this helps!
Answer:
The final size is approximately equal to the initial size due to a very small relative increase of
in its size
Solution:
As per the question:
The energy of the proton beam, E = 250 GeV =
Distance covered by photon, d = 1 km = 1000 m
Mass of proton, 
The initial size of the wave packet, 
Now,
This is relativistic in nature
The rest mass energy associated with the proton is given by:


This energy of proton is 
Thus the speed of the proton, v
Now, the time taken to cover 1 km = 1000 m of the distance:
T = 
T = 
Now, in accordance to the dispersion factor;


Thus the increase in wave packet's width is relatively quite small.
Hence, we can say that:

where
= final width
Answer:
Average velocity is the displacement of an object over time that also in a specified direction...
Explanation:
brainliest plz
F = ma
m = F/a
m = 20N / 5m/s^2
m = 4kg