The free-fall acceleration on the second planet is one-fourth the value of the first planet.
Calculation:
Consider the mass of planet A to be, M
the mass of planet B to be, Mₓ = M
the radius of planet A to be, R₁
the radius of planet B to be, R₂
The acceleration due to gravity on planet A's surface is given as:
g = GM/R₁² - (1)
Similarly, the acceleration due to gravity on planet B's surface is given as:
g' = GM/R₂² [where, R₂ = 2R₁]
= GM/4R₁² -(2)
From equation 1 & 2, we get:
g/g' = GM/R₁² ÷ GM/4R₁²
g/g' = 4/1
Thus we get,
g' = 1/4 g
Therefore, the free-fall acceleration on the second planet is one-fourth the value of the first planet.
Learn more about free-fall here:
<u>brainly.com/question/13299152</u>
#SPJ4
