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Tpy6a [65]
4 years ago
5

A 95.0kg weightlifter pushes on a 800,000 kg wall for 400s but it does not move. How much work does he do on the wall?

Physics
1 answer:
Soloha48 [4]4 years ago
7 0
<span>The weightlifter does no work. Although he has exerted force, work is the product of force over distance. Since he has not moved the wall he has done no work.</span>
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Answer:

The velocity with which the mass will hit the floor is v_f = \sqrt{2(\dfrac{m_2-m_1}{m_2+m_1}) x.}

Explanation:

If the tension in the string is T, for m_1 we have

T- m_1g =m_1a,

and for the mass m_2

T -m_2g = -m_2a

From these equations we solve for a and get:

a =(\dfrac{m_2-m_1}{m_2+m_1}) g.

The kinematic equation

v_f^2 = v_0^2+2ax

gives the final velocity v_f of a particle, when its initial velocity was v_0, and has traveled a distance x while undergoing acceleration a.

In our case

v_0 = 0 (the initial velocity of the particles is zero)

a =(\dfrac{m_2-m_1}{m_2+m_1}) g.

which gives us

v_f^2 = 2ax

v_f^2 =2(\dfrac{m_2-m_1}{m_2+m_1}) g

\boxed{v_f = \sqrt{2(\dfrac{m_2-m_1}{m_2+m_1}) x.} }

which is the velocity with which the mass m_2 will hit the floor.

8 0
3 years ago
When a force acts on an object from an angle other than either 0° or 180° to the direction of motion:
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You must find the component of the force before calculating
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3 years ago
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g100num [7]

Answer:

D

Explanation:

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Answer:

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Force is applied to an object and the object is moved over a distance in the same direction of the applied force" is the definit
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Explanation:

The expression for the work done in terms of force and displacement is as follows;

W= Fd

Here, W is the work done, F is the applied force and d is the displacement.

If the force is applied to an object and the object is displaced to some distance then the work is done.

It is given in the problem that force is applied to an object and the object is moved over a distance in the same direction of the applied force". The given statement is the definition of work. The work done can be zero, negative and positive. In the given case, the positive work is said to be done as the direction of the applied force and the distance moved by the object are same.

Therefore, the correct option is (d).

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3 years ago
Read 2 more answers
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