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4 years ago

Which gas contributes most to the greenhouse effect?

2 answers:

4 0

Water vapor contributes most to the natural greenhouse effect. Carbon Dioxide (CO2) contributes most to the accelerated greenhouse effect which is causing <span>global warming.</span>

Murrr4er [49]4 years ago

3 0

The answer is D) Carbon dioxide.
Hope this helps

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On a frozen pond, a 8.54-kg sled is given a kick that imparts to it an initial speed of ð£0=1.87 m/s. The coefficient of kinetic

zhannawk [14.2K]

Answer:2.05 m

Explanation:

Given

Mass of sled $m=8.54 kg$

initial speed $u=0.187 m/s$

coefficient of kinetic Friction $\mu _k=0.087$

According to work-energy theorem work done by all the forces is change in Kinetic energy

$W_{friction}=\frac{1}{2}mv_i^2-\frac{1}{2}mv_f^2$

$\mu _kmg\times d=\frac{1}{2}\times 8.54\times 1.87^2$ ,where d= distance moved

$0.087\times 8.54\times 9.8\times d=14.93$

$d=\frac{14.93}{7.281}$

$d=2.05 m$

4 0

3 years ago

When a molecule absorbs an infrared photon it contributes to the ________energy of that molecule.

Tpy6a [65]

Answer: INFRARED ENERGY

5 0

4 years ago

a0.155 kg arrow is shot from ground level, upward at 31.4 m/s. what is its kinetic energy (ke) when it is 30.0 m above the groun

swat32

The kinetic energy (KE) of a 0.155 kg arrow that is shot from ground level, upward at 31.4 m/s, when it is 30.0 m above the ground is 30.85 J

Assuming air friction is negligible,

a = - 9.8 m / s²

u = 31.4 m / s

s = 30 m

v² = u² + 2 a s

v² = 31.4² + ( 2 * - 9.8 * 30 )

v² = 985.96 - 588

v² = 397.96 m / s

KE = 1 / 2 m v²

KE = 1 / 2 * 0.155 * 397.96

KE = 0.0775 * 397.96

KE = 30.85 J

Therefore, the kinetic energy ( KE ) when it is 30.0 m above the ground is 30.85 J

To know more about kinetic energy

brainly.com/question/24360064

#SPJ1

5 0

2 years ago

Is Kepler's constant the same for moons orbiting a planet as it is for planets orbiting the sun? Why?

d1i1m1o1n [39]

Yes because we have day and night and seasons

7 0

3 years ago

Read 2 more answers

A policeman investigating an accident measures the skid marks left by a car on the horizontal road. He determines that the dista

sleet_krkn [62]

<h2>The velocity of car was m m/s </h2>

Explanation:

When the car skids , its centripetal force is provided by frictional force .

Here centripetal force F = $\frac{mv^2}{r}$

here v is the velocity of car and r is the radius of the curve .

The frictional force f = μ R

here μ is the coefficient of kinetic friction and R is normal reaction

Thus f = m g

On horizontal road R = mg

Thus F = f at the time of skid .

Thus v = $\sqrt{\mu rg}$

= $\sqrt{0.29x23.74x10}$ = 9 m/s

3 0

3 years ago