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pickupchik [31]
3 years ago
11

A different solution with an H+ concentration of 1.0 × 10–4 would have a pH = .

Chemistry
1 answer:
tekilochka [14]3 years ago
7 0
1×10^-4 = 0,0001M

pH = -log[H+]
pH = -log0,0001
pH = 4
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The solubility of lead(II) iodide is 0.064 g/100 mL at 20ºC. What is the solubility product for lead(II) iodide?
quester [9]

Answer:

Ksp=1.07x10^{-8}

Explanation:

Hello,

In this case, the dissociation reaction is:

PbI_2(s)\rightleftharpoons Pb^{2+}(aq)+2I^-(aq)

For which the equilibrium expression is:

Ksp=[Pb^{2+}][I^-]^2

Thus, since the saturated solution is 0.064g/100 mL at 20 °C we need to compute the molar solubility by using its molar mass (461.2 g/mol)

Molar solubility=\frac{0.064g}{100mL}*\frac{1000mL}{1L}*\frac{1mol}{461.2g}=1.39x10^{-3}M

In such a way, since the mole ratio between lead (II) iodide to lead (II) and iodide ions is 1:1 and 1:2 respectively, the concentration of each ion turns out:

[Pb^{2+}]=1.39x10^{-3}M

[I^-]=1.39x10^{-3}M*2=2.78x10^{-3}M

Thereby, the solubility product results:

Ksp=(1.39x10^{-3}M)(2.78x10^{-3}M)^2\\\\Ksp=1.07x10^{-8}

Regards.

6 0
4 years ago
How many seconds are in a 5.5 ms
deff fn [24]

Answer:

0.0055 seconds

Explanation:

To answer this question you need to know the equivalence:

1 second (s) = 5.5 (miliseconds) (ms)

Then you use the conversion factor:

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5.5ms

- Put in the denominator the equivalence with the same units:

5.5ms*\frac{}{1000ms}

- Put in the numerator the unit at which you want to convert the value given:

5.5ms*\frac{1s}{1000ms}

- Then multiply and divide the quantities:

5.5ms*\frac{1s}{1000ms}=0.0055 s

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8 0
3 years ago
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Answer:

Answer. 600 g CaCl2 would be required to make 2 L of a 3.5 M solution.

7 0
4 years ago
You have 4 moles of oxygen gas in a flask. 4 moles of helium gas is added. What happens to the total pressure of the gases in th
ASHA 777 [7]

Answer: The correct option is (c). The total pressure doubles.

Solution:

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p_{O_2}=Tp_1\times 1=Tp_1....(1)

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Final total pressure when 4 moles of helium gas were added:

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partial pressure of oxygen in the mixture :

Since, the number of moles of oxygen remains the same, the partial pressure of oxygen will also remain the same in the mixture.

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Tp_2= Total pressure of the mixture.

from (1)

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On rearranging, we get:

Tp_2=2\times Tp_1

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7 0
3 years ago
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MrRa [10]

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Explanation: The volume of the balloon is 400 m3. To what temperature must the air in the balloon be heated before the balloon will lift off. (Air density at 10 oC is 1.25 kg/m3.)

3 0
3 years ago
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