Answer:

Explanation:
Hello,
In this case, the dissociation reaction is:

For which the equilibrium expression is:
![Ksp=[Pb^{2+}][I^-]^2](https://tex.z-dn.net/?f=Ksp%3D%5BPb%5E%7B2%2B%7D%5D%5BI%5E-%5D%5E2)
Thus, since the saturated solution is 0.064g/100 mL at 20 °C we need to compute the molar solubility by using its molar mass (461.2 g/mol)

In such a way, since the mole ratio between lead (II) iodide to lead (II) and iodide ions is 1:1 and 1:2 respectively, the concentration of each ion turns out:
![[Pb^{2+}]=1.39x10^{-3}M](https://tex.z-dn.net/?f=%5BPb%5E%7B2%2B%7D%5D%3D1.39x10%5E%7B-3%7DM)
![[I^-]=1.39x10^{-3}M*2=2.78x10^{-3}M](https://tex.z-dn.net/?f=%5BI%5E-%5D%3D1.39x10%5E%7B-3%7DM%2A2%3D2.78x10%5E%7B-3%7DM)
Thereby, the solubility product results:

Regards.
Answer:
0.0055 seconds
Explanation:
To answer this question you need to know the equivalence:
1 second (s) = 5.5 (miliseconds) (ms)
Then you use the conversion factor:
-Put the value given and the units:

- Put in the denominator the equivalence with the same units:

- Put in the numerator the unit at which you want to convert the value given:

- Then multiply and divide the quantities:

Note that the same units in numerator and denominator are cancelled.
Answer:
Answer. 600 g CaCl2 would be required to make 2 L of a 3.5 M solution.
Answer: The correct option is (c). The total pressure doubles.
Solution:
Initially, only 4 moles of oxygen gas were present in the flask.
(
) ( according to Dalton's law of partial pressure)
....(1)
= Total pressure when only oxygen gas was present.
Final total pressure when 4 moles of helium gas were added:

partial pressure of oxygen in the mixture :
Since, the number of moles of oxygen remains the same, the partial pressure of oxygen will also remain the same in the mixture.

= Total pressure of the mixture.
from (1)

On rearranging, we get:

The new total pressure will be twice of initial total pressure.
Answer:Answer:5.95 LExplanation:V1/V2 = T1/T24.82 L/V2 = 243.1K/300.1KV2 = 4.82*300.1/243.1 L = 5.95 L
Explanation: The volume of the balloon is 400 m3. To what temperature must the air in the balloon be heated before the balloon will lift off. (Air density at 10 oC is 1.25 kg/m3.)