Answer:
2HgO → 2Hg + O₂
The reaction is a decomposition reaction because from one reactant two products were obtained
Explanation:
The problem here involves balancing the chemical reaction given and also classifying the reaction.
The unbalanced expression is given as:
HgO → Hg + O₂
Assign the alphabets a,b and c as coefficients that will balance the equation
aHgO → bHg + cO₂
Conserving Hg: a = b
O: a = 2c
So, let c = 1, a = 2 b = 2
Therefore;
2HgO → 2Hg + O₂
The reaction is a decomposition reaction because from one reactant two products were obtained
2 Fluorine atoms covalently bonded with each other, each sharing an equal number of a single, one valence electron to achieve a stable octet, would form a diatonic fluorine gas. It is a diatomic molecule, a molecule consisting of 2 atoms that are the same, in this case fluorine.
The main reason for this is Average bond of O₂ is shorter and strong from O₃.
<h3>What is ozone?</h3>
Ozone is a blue gas composed of three oxygen atoms bonded together.
It occurs naturally high up in the Earth's atmosphere, where it protects the surface from harmful ultraviolet (UV) rays,
UV radiation will dissociate ozone into an oxygen atom and an oxygen molecule.
Ozone molecules are tetrahedral so the bond angle is 109 degree the electrons in the double bond occupy more space that the non-bonding electron pair.
Oxygen has a small size that leads to smaller O-O bond length.
A lone pair of electrons on both the oxygen repel each other leading to weakening of O-O bond.
O3 has longer and weaker bonds than O2, whereas SO2 has shorter and stronger bonds than SO.
Molecular oxygen, O2, is photolyzed by light of 241 nm and has a bond energy of 498 kJ/mol.
The main reason for this is Average bond of O₂ is shorter and strong from O₃.
Learn more about ozone, Here:
brainly.com/question/27911475
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Answer:
HCl (aq) + NaOH (aq) --> H2O (L) + NaCl (aq)
Explanation:
HCl is a strong acid while NaOH is a strong alkali. Hence both should dissociate completely in water and 1 mol of HCl will fully neutralise 1 mol of NaOH.
I'm assuming that Part 2 on molarity is part of a data based question that requires you to calculate the number of moles of NaOH based on the data provided and the equation that you are required to balance. Hence, I can't help you with it as I do not have the values.