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sineoko [7]
4 years ago
10

Select Light for the type of wave, adjust the wavelength so that the light is red, and increase the amplitude of the light to th

e max. Then, select the start button at the source location to begin producing the waves. Light is a form of electromagnetic wave, containing oscillating electric and magnetic fields. The wave amplitude detector mentioned above shows how the electric field oscillates in time at the location of the probe. The amplitude of the wave at the location of the probe is equal to the maximum electric field measured. How does the amplitude of the wave depend on the distance from the source?
Physics
1 answer:
Sergeu [11.5K]4 years ago
5 0

Answer:

here as we increase the distance the intensity will decrease and hence the amplitude of the electric field will decrease and vice-versa

Explanation:

As wee know that the amplitude of the wave will decide the energy of the wave

Here we know that energy density of electromagnetic wave is given as

u = \frac{1}{2}\epsilon_0E_0^2

now we have

\frac{I}{c} = \frac{1}{2}\epsilon_0 E_0^2

so here we can say that intensity of the wave at the given distance from the source is given by formula

I = \frac{P}{4\pi r^2}

so here as we increase the distance the intensity will decrease and hence the amplitude of the electric field will decrease and vice-versa.

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3 years ago
A uniform meter stick is hung at its center from a thin wire. It is twisted and oscillates with a period of 5 s. The meter stick
rewona [7]

Answer:

The new time period is  T_2 =  3.8 \  s

Explanation:

From the question we are told that

  The period of oscillation is  T =  5 \ s

   The  new  length is  l_2  =  0.76  \ m

Let assume the original length was l_1 = 1 m

Generally the time period is mathematically represented as

         T  =  2 \pi   \sqrt{ \frac{ I }{ mgh } }

Now  I is the moment of inertia of the stick which is mathematically represented as

           I  =  \frac{m * l^2 }{12 }

So

        T  =  2 \pi   \sqrt{ \frac{  m * l^2 }{12 *   mgh } }

Looking at the above equation we see that

        T  \ \ \  \alpha  \ \ \  l

=>    \frac{ T_2 }{T_1}  =  \frac{l_2}{l_1}

=>    \frac{ T_2}{5} =  \frac{0.76}{1}

=>     T_2 =  3.8 \  s

3 0
4 years ago
Can someone please help me
Delicious77 [7]

Answer:

I am 98% sure that the answers are B and A

Explanation:

6 0
2 years ago
Refraction or the bending of waves takes place when a light wave changes A) color. B) frequency. C) intensity. D) speed.
DENIUS [597]
The answer is D. speed
6 0
4 years ago
Read 2 more answers
Introduction: The specific heat capacity of a substance is the amount of energy needed to change the temperature of that substan
ki77a [65]

Answer:

A) 8,368 J

B) ) 0.893 J/gºC

Explanation:

A)

  • The heat gained by the water can be obtained solving the following equation:

       q_{g} = c_{w} * m *  \Delta T (1)

  • where cw = specific heat of water = 4.184 J/gºC
  • m= mass of water = 1,000 g
  • ΔT = 2ºC
  • Replacing these values in (1) we get:

       q_{g} = c_{w} * m *  \Delta T = 4.184 J/gºC*1,000 g* 2ºC = 8,368 J (2)

B)

  • Assuming that the heat energy gained by the water is equal to the one lost by the aluminum, we can use the same equation, taking into account that the energy is lost by the aluminum, so the sign is negative:  -8,368 J.
  • Replacing by the mass of aluminum (125 g), and the change in temperature (-74.95ºC), in (1), we can solve for the specific heat of aluminum, as follows:

       q_{l} = c_{Al} * m_{Al} *  \Delta T  (3)

⇒    -8,368 J = c_{Al}* 125 g * (-74.95ºC) (4)

       c_{Al} = \frac{-8,368J}{125g*(-74.95ºC} = 0.893 J/gºC (5)

  • which is pretty close to the Aluminum's accepted specific heat value of 0.900 J/gºC.

8 0
3 years ago
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