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poizon [28]
1 year ago
13

A flash of red light and a flash of blue light enter a glass cube perpendicular to its surface at the same time. after passing t

hrough the block, the ____ pulse exits first
Physics
1 answer:
Wewaii [24]1 year ago
7 0

A flash of red light and a flash of blue light enter a glass cube perpendicular to its surface at the same time. after passing through the block, the red light pulse exits first.

For any medium, other than vacuum, the index of refraction for red light is slightly lower (closer to 1 ) than that for blue light. This means that when light goes from vacuum (or air) into glass, the red light deviates from its original direction less than does the blue light. Also, as the light reemerges from the glass into vacuum (or air), the red light again deviates less than the blue light. If the two surfaces of the glass are parallel to each other, the red and blue rays will emerge traveling parallel to each other, but displaced laterally from one another.

what is refractive index?

The ratio between the speed of light in medium to speed in a vacuum is the refractive index. When light travels in a medium other than the vacuum, the atoms of that medium continually absorb and re-emit the particles of light, slowing down the speed light.

learn more about refractive index from here: brainly.com/question/28203787

#SPJ4

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Reading a book in your warm, comfy seat ... in Row-27 of a
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Define linear expansivity
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. A spring has a length of 0.200 m when a 0.300-kg mass hangs from it, and a length of 0.750 m when a 1.95-kg mass hangs from it
kap26 [50]

Answer:

29.4 N/m

0.1  

Explanation:

a) From the restoring Force we know that :  

F_r = —k*x  

the gravitational force :  

F_g=mg  

Where:

F_r is the restoring force .

F_g is the gravitational force

g is the acceleration of gravity

k is the constant force  

xi , x2 are the displacement made by the two masses.

Givens:

<em>m1 = 1.29 kg</em>

<em>m2 = 0.3 kg  </em>

<em>x1   = -0.75 m  </em>

<em>x2 = -0.2 m </em>

<em>g   = 9.8 m/s^2  </em>

Plugging known information to get :

F_r =F_g

-k*x1 + k*x2=m1*g-m2*g

k=29.4 N/m

b) To get the unloaded length 1:  

l=x1-(F_1/k)

Givens:

m1 = 1.95kg , x1 = —0.75m  

Plugging known infromation to get :

l= x1 — (F_1/k)  

= 0.1  

 

3 0
3 years ago
In which region of the periodic table do the elements NOT normally react chemically with other elements?
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We would say that it would be metals.

6 0
3 years ago
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A charged particle is observed traveling in a circular path in a uniform magnetic field. If the particle had been traveling four
8090 [49]

Answer:

The new radius of the trajectory of the particle is four times the previous radius

Explanation:

In order to know what is the radius of the trajectory of the charged particle, if its speed is four times as fast, you take into account the following formula, which describes the radius of a charged particle in a magnetic field:

r=\frac{mv}{qB}          (1)

If the speed of the particle is for time as fast, that is, v' = 4v, you obtain, in the equation (1):

r'=\frac{mv'}{qB}=\frac{m(4v)}{qB}=4\frac{mv}{qB}=4r

The new radius of the trajectory of the particle is four times the previous radius

8 0
2 years ago
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