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4 years ago

What would happen if you left your dichloromethane/ethanol solvent mixtures uncovered?

1 answer:

3 0

Dichloromethane/ethanol solvent mixtures are substances composed of compounds that has a very high volatility. The higher the volatility of the substances, the faster it is for them to vaporized.

If we leave the solution or the mixture uncovered then, it is easier for the vapors produced to escape the system to the atmosphere.

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What is the use of a pedigree chart? Please do not answer wat a perigee chart is!.

FinnZ [79.3K]

Pedigree charts are used to see traits that are present in families or individuals. For example, it can be used see if certain diseases are running through someone's family and if that individual will inherit the disease.

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4 years ago

Read 2 more answers

Example of oxidizing agents include

Ivahew [28]

Explanation:

Substances generally tends to specialize as either oxidizing or reducing agents.

An oxidizing agent is an electron acceptor which causes a co-reactant to be oxidized in a reaction.

Examples are:

Non-metals especially oxygen and the halogens.

Other examples are H₂SO₄ , HNO₃, KMnO₄, K₂Cr₂O₇

learn more:

Oxidizing and reducing agents brainly.com/question/5558762''

#learnwithBrainly

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4 years ago

Nuclear reactions are different from chemical reactions, because in nuclear reactions, the transformations between species don't

Lorico [155]

That is true. the nuclei change in nuclear rxns. Chemical rnxs use electrons..

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3 years ago

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Calcium carbonate has the chemical formula CaCO3. A certain quantity of calcium carbonate has 8.35x1025 atoms. How many moles of

kotegsom [21]

Answer

27.7 moles

Explanation:

Data Given:

Chemical formula of Calcium carbonate = CaCO₃

no. of atoms of CaCO₃ = 8.35 x 10²⁵ atoms

moles of CaCO₃= ?

Solution

First convert number of atoms to number of molecules

we have 5 atoms per molecule then how many molecules will be for 8.35 x 10²⁵ atoms

So, apply unity formula

5 atoms ≅ 1 molecule of CaCO₃

8.35 x 10²⁵ atoms ≅ X molecule of CaCO₃

by doing cross multiplication

X molecule of CaCO₃ = 8.35 x 10²⁵ atoms x 1 molecule / 5 atoms

X molecule of CaCO₃ = 1.67 x 10²⁵ molecule

Formula will be used

no. of moles = no. of molecules / Avogadro's number . . . . (1)

Where

Avogadro's number = 6.022 x 10²³ molecules/mol

So,

Put values in equation 1

no. of mole = 1.67 x 10²⁵/ 6.022 x 10²³ (molecules/mol)

no. of mole = 27.7 moles

So,

moles of CaCO₃ = 27.7 moles

5 0

4 years ago

The questions are attached

Sladkaya [172]

Answer:

Explanation:

a) Balanced chemical equation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

b) Mass of oxygen gas needed = ?

Mass of propane = 25 g

Solution:

Number of moles of propane = mass/molar mass

Number of moles = 25 g/ 44.1 g/mol

Number of moles = 0.57 mol

now we will compare the moles of oxygen and propane:

C₃H₈ : O₂

1 : 5

0.57 : 5/1×0.57 = 2.85 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 2.85 mol × 32 g/mol

Mass = 91.2 g

c) water vapors produced = ?

Mass of propane = 25 g

Solution:

Number of moles of propane = mass/molar mass

Number of moles = 25 g/ 44.1 g/mol

Number of moles = 0.57 mol

now we will compare the moles of water and propane:

C₃H₈ : H₂O

1 : 4

0.57 : 4/1×0.57 = 2.28 mol

Mass of water vapors:

Mass = moles × molar mass

Mass = 2.28 mol × 18 g/mol

Mass = 41.0 g

mass of water vapors produced = 1.5 kg (1500 g)

Mass of propane reacted = ?

Solution:

Number of moles of water vapors:

Number of moles = mass/molar mass

Number of moles = 1500 g/ 18 g/mol

Number of moles = 83.33 mol

now we will compare the moles of water and propane.

H₂O : C₃H₈

4 : 1

83.3 : 1/4×83.3 = 20.8 mol

Mass of propane:

Mass = number of moles ×molar mass

Mass = 20.8 mol × 44.1 g/mol

Mass = 917 g

3 0

3 years ago