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Answer
given,
current (I) = 16 mA
circumference of the circular loop (S)= 1.90 m
Magnetic field (B)= 0.790 T
S = 2 π r
1.9 = 2 π r
r = 0.3024 m
a) magnetic moment of loop
M= I A
M=![16 \times 10^{-3} \times \pi \times r^2](https://tex.z-dn.net/?f=16%20%5Ctimes%2010%5E%7B-3%7D%20%5Ctimes%20%5Cpi%20%5Ctimes%20r%5E2)
M=![16 \times 10^{-3} \times \pi \times 0.3024^2](https://tex.z-dn.net/?f=16%20%5Ctimes%2010%5E%7B-3%7D%20%5Ctimes%20%5Cpi%20%5Ctimes%200.3024%5E2)
M=![4.59 \times 10^{-3}\ A m^2](https://tex.z-dn.net/?f=4.59%20%5Ctimes%2010%5E%7B-3%7D%5C%20A%20m%5E2)
b) torque exerted in the loop
![\tau = M\ B](https://tex.z-dn.net/?f=%5Ctau%20%3D%20M%5C%20B)
![\tau = 4.59 \times 10^{-3}\times 0.79](https://tex.z-dn.net/?f=%5Ctau%20%3D%204.59%20%5Ctimes%2010%5E%7B-3%7D%5Ctimes%200.79)
![\tau = 3.63 \times 10^{-3} N.m](https://tex.z-dn.net/?f=%5Ctau%20%3D%203.63%20%5Ctimes%2010%5E%7B-3%7D%20N.m)
No "might<span>". The amount of CO2 in the </span>atmosphere<span> HAS gone up since the start of industrialisation as the result of </span>burning fossil fuels<span>.</span>
Answer:
P = 227 N
Explanation:
Assuming the crate is on horizontal ground and subject to a horizontal force.
F = ma
P - μmg = ma
P = m(a + μg)
P = m(v²/2s + μg)
P = 50(4²/(2(5))+ 0.3(9.8))
P = 227 N
Answer:
532 millimeters of mercury
Explanation:
In order to convert the pressure from atm to millimeters of mercury (mm Hg), we should remind the conversion factor between the two units:
1 atm = 760 mm Hg
Therefore, we can solve the problem by setting up the following proportion:
![1 atm : 760 mmHg = 0.700 atm : x](https://tex.z-dn.net/?f=1%20atm%20%3A%20760%20mmHg%20%3D%200.700%20atm%20%3A%20x)
Solving for x, we find
![x=\frac{(760 mmHg)(0.700 atm)}{1 atm}=532 mmHg](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B%28760%20mmHg%29%280.700%20atm%29%7D%7B1%20atm%7D%3D532%20mmHg)