The flow of electrons in the circuit will be less.
Answer:
A
Explanation:
A and B are isotopes of one another but the same element
C and D are isotopes of one another but the same element
However, A and B have a different proton count than C and D, indicating different elements because the proton count is equivalent to the atomic number.
<span>During
adverse weather conditions such as rain or fog, drivers should take
action accordingly by turning on their headlights, slowing down and
increasing following distance. Adverse weather means that you are driving in difficult and dangerous conditions. Increasing following distance will help you to maintain safe driving and avoid tailgating. </span>
Answer: - 452.088joule
Explanation:
Given the following :
Mass of water = 12g
Change in temperature(Dt) = (11 - 20)°C = - 9°C
Specific heats capacity of water(c) = 4.186j/g°C
Q = mcDt
Where Q = quantity of heat
Q = 12g × 4.186j/g°C × - 9°C
Q = - 452.088joule
Answer:
Radius of cross section, r = 0.24 m
Explanation:
It is given that,
Number of turns, N = 180
Change in magnetic field, 
Current, I = 6 A
Resistance of the solenoid, R = 17 ohms
We need to find the radius of the solenoid (r). We know that emf is given by :


Since, E = IR




or

Area of circular cross section is, 


r = 0.24 m
So, the radius of a tightly wound solenoid of circular cross-section is 0.24 meters. Hence, this is the required solution.