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3 years ago

6

Circle the letter of the sentence that tells how Bohr' model of the atom differed from Rutherford's model A. Bohr's model focuse

d on the nucleus B. Bohr's model focused on the protons C. Bohr's model focused on the neutrons D. Bohr's model focused on the electrons

1 answer:

photoshop1234 [79]3 years ago

4 0

Answer:

A. Bohr's model focused on the nucleus

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CN you help me with this question?

qaws [65]

25% i believe because if were talking 50 percent half it would be 25.

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3 years ago

Waves in a fish bowl jostled by the Thingamajigger move to the sides at an average velocity of 0.50 m/s. If they occur once ever

Colt1911 [192]

Answer:

0.125 m

Explanation:

In this problem, we have:

v = 0.50 m/s is the average velocity of the wave

T = 0.25 s is the period of the wave

We can find the frequency of the wave, which is equal to the reciprocal of the period:

$f=\frac{1}{T}=\frac{1}{0.25 s}=4 Hz$

The problem is asking us to find the distance between two crests of the wave: this is equivalent to the wavelength. The wavelength is related to the average velocity and the frequency by the formula:

$\lambda=\frac{v}{f}$

Substituting the numerical values, we find

$\lambda=\frac{0.5 m/s}{4 Hz}=0.125 m$

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3 years ago

Name and explain two sleeping disorders

vfiekz [6]

Insomnia and night terrors

4 0

3 years ago

Will give brainliest!

tamaranim1 [39]

Howdy!!

your answer is ----

total resistance 1/R = 1/9+1/9+1/9
= 3/9

=> R = 9/3 = 3 ohm
according to ohms law

voltage = current × resistance

= 4 × 3 = 12 volt

hope it help you

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3 years ago

A 544 g ball strikes a wall at 14.3 m/s and rebounds at 14.4 m/s. The ball is in contact with the wall for 0.042 s. What is the

Nezavi [6.7K]

Answer:

$F = 371.738\,N$

Explanation:

Let assume that ball strikes a vertical wall in horizontal direction. The situation can be modelled by the appropriate use of the definition of Moment and Impulse Theorem, that is:

$(0.544\,kg)\cdot (14.3\,\frac{m}{s})-F\cdot \Delta t = -(0.544\,kg)\cdot (14.4\,\frac{m}{s} )$

$F\cdot \Delta t = 15.613\,\frac{kg}{m\cdot s}$

The average force acting on the ball during the collision is:

$F = \frac{15.613\,\frac{kg}{m\cdot s} }{0.042\,s}$

$F = 371.738\,N$

3 0

3 years ago

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