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marin [14]
3 years ago
15

Which shows a decrease in fluid pressure? A. Water in a creek slows down as it enters a slow-moving river. B. Oxygen is compress

ed as it is put into a pressurized tank. C. A river speeds up when it moves into a narrower channel. D. A fan is turned on high speed to low speed.
Physics
2 answers:
Dahasolnce [82]3 years ago
7 0

Answer:

A

Explanation

Becasue the water level is decreasing

Ainat [17]3 years ago
3 0

Answer:

Option D.

A fan is turned from high speed to low speed.

Explanation:

It is important to note that air is also a fluid.

In a system, static pressure of air increases with the speed of rotation of the fan. This is because when the speed of the fan is increased, the force with which it is pushing the air molecules is increased. Since pressure is a relationship between force and area, the pressure of the air molecules will be increased.

Conversely, when the speed of the fan is reduced, the priming force on the air molecules will be reduced, hence the pressure of the air will drop.

This makes option D the correct option

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Read 2 more answers
A car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.62 m/s2 for t1 = 20 s. At that point the
arsen [322]

Total displacement of the car: 405 m

Explanation:

The first part of the motion of the car is a uniformly accelerated motion, so we can use the suvat equation

s_1=ut_1+\frac{1}{2}a_1 t_1^2

where:

u = 0 is the initial velocity (the car starts from rest)

t_1 = 20 s is the time elapsed in the 1st part

a_1=1.62 m/s^2 is the acceleration of the car in the 1st part

s_1 is the displacement of the car in the 1st part

Solving for s_1,

s_1=0+\frac{1}{2}(1.62)(20)^2=324 m

We can also find the velocity of the car after these 20 seconds using the equation:

v_1 = u +a_1 t_1 = 0 + (1.62)(20)=32.4 m/s

Now we can find the distance covered by the car in the 2nd part, where it decelerates after having seen the tree limb on the road. We can do it by using the suvat equation:

s_2 = (\frac{v_1 + v_2}{2})t_2

where:

v_1=32.4 m/s is the initial velocity at the beginning of the 2nd phase

v_2=0 is the final velocity (the car comes to a stop)

t_2=5 s is the time elapsed in the 2nd phase

Substituting,

s_2=\frac{32.4+0}{2}(5)=81 m

So, the total displacement of the car is

s=s_1+s_2=324+81=405 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

3 0
3 years ago
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