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marin [14]
3 years ago
15

Which shows a decrease in fluid pressure? A. Water in a creek slows down as it enters a slow-moving river. B. Oxygen is compress

ed as it is put into a pressurized tank. C. A river speeds up when it moves into a narrower channel. D. A fan is turned on high speed to low speed.
Physics
2 answers:
Dahasolnce [82]3 years ago
7 0

Answer:

A

Explanation

Becasue the water level is decreasing

Ainat [17]3 years ago
3 0

Answer:

Option D.

A fan is turned from high speed to low speed.

Explanation:

It is important to note that air is also a fluid.

In a system, static pressure of air increases with the speed of rotation of the fan. This is because when the speed of the fan is increased, the force with which it is pushing the air molecules is increased. Since pressure is a relationship between force and area, the pressure of the air molecules will be increased.

Conversely, when the speed of the fan is reduced, the priming force on the air molecules will be reduced, hence the pressure of the air will drop.

This makes option D the correct option

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I believe its the third answer
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2 years ago
A circular loop of radius r carries a current i. at what distance along the axis of the loop is the magnetic field one-half its
lana [24]

At r = 0.766 R the magnetic field intensity will be half of its value at the center of the current carrying loop.

We have a circular loop of radius ' r ' carrying current ' i '.

We have to find at what distance along the axis of the loop is the magnetic field one-half its value at the center of the loop.

<h3>What is the formula to calculate the Magnetic field intensity due to a current carrying circular loop at a point on its axis?</h3>

The formula to calculate the magnetic field intensity due to a current carrying ( i ) circular loop of radius ' R ' at a distance ' x ' on its axis is given by -

B(x) = \frac{\mu_{o} iR^{2} }{2(x^{2} +R^{2})^{\frac{3}{2} } }

Now, for magnetic field intensity at the center of the loop can calculated by putting x = 0 in the above equation. On solving, we get -

B(0) = \frac{\mu_{o} i}{2R}

Let us assume that the distance at which the magnetic field intensity is one-half its value at the center of the loop be ' r '. Then -

\frac{\mu_{o} iR^{2} }{2(r^{2} +R^{2})^{\frac{3}{2} } } = \frac{1}{2} \frac{\mu_{o}i }{2R}

2R^{3} = (r^{2} +R^{2} )^{\frac{3}{2} }

4R^{6} = (r^{2} +R^{2} )^{3}

r^{2} =0.587R^{2}

r = 0.766R

Hence, at r = 0.766 R - the magnetic field intensity will be half of its value at the center of the current carrying loop.

To solve more questions on magnetic field intensity, visit the link below-

brainly.com/question/15553675

#SPJ4

6 0
2 years ago
In a Compton scattering experiment, scattered photon is found to have its wavelength three times of the incident photon for the
Svetlanka [38]

Answer:

Two of Einstein’s influential ideas introduced in 1905 were the theory of special relativity and the concept of a light quantum, which we now call a photon. Beyond 1905, Einstein went further to suggest that freely propagating electromagnetic waves consisted of photons that are particles of light in the same sense that electrons or other massive particles are particles of matter. A beam of monochromatic light of wavelength \lambda (or equivalently, of frequency f) can be seen either as a classical wave or as a collection of photons that travel in a vacuum with one speed, c (the speed of light), and all carrying the same energy, {E}_{f}=hf. This idea proved useful for explaining the interactions of light with particles of matter.

5 0
4 years ago
Suppose that there are N=108 two-state systems, each with energy difference E=6 × 10-21 J between the two states. The environmen
kati45 [8]

Answer:

The value of \dfrac{dU}{dM} is 6\times10^{-29}\ J/unit.

Explanation:

Given that,

Number N=10^{8}

Energy difference = 6\times10^{-21}\ J[/tex]

Temperature T =300 K

We need to calculate the value of \dfrac{dU}{dM}

We know that,

\dfrac{dU}{dM}=\dfrac{energy\ difference}{Change\ in\ number\ of\ system}

\dfrac{dU}{dM}=\dfrac{6\times10^{-21}}{10^{8}}

\dfrac{dU}{dM}=6\times10^{-29}\ J/unit

Hence, The value of \dfrac{dU}{dM} is 6\times10^{-29}\ J/unit.

5 0
4 years ago
A car moves from rest condition moves with acceleration 4 ms^-2.After 5s,calculate velocity of the car and the distance traveled
lisov135 [29]

Answer:

1) 20 m/s

2) 60 meters

Explanation:

with a constant acceleration of 4m/s/s, the vehicle will end up traveling at 20 m/s after 5 seconds, and will have travelled 60 meters.

5 0
4 years ago
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