1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
solmaris [256]
3 years ago
10

A ball is tossed straight up from the surface of a small, sphericalasteroid with no atmosphere. The aball rises to a height equa

l tothe asteroid's raidus and then falls straight down toward thesurface of the asteroid.
1. What forces act on the ball while it is on the way up?

1) only a decreasing gravitational force that acts downward.
2) only an increasing gravitational forces that acts downward
3) only a constant gravitation force that acts downward
4) both a constant gravitational force that acts downward and adecreasing force that acts upward
5) no forces act on the ball

2. the acceleration of the ball at the top of its path is1) at its max vlue for the ball's flightb) Equal to the accleration at the surface of the asteroidc) equal to .5 the acceleration at the surface of the asteroidd) equal to 1/4 the acceleration at the surface of theasteroide) zero
Physics
1 answer:
Anastaziya [24]3 years ago
4 0

Answer:

1. 3) only a constant gravitation force that acts downward

2. b) Equal to the accleration at the surface of the asteroidc)

Explanation:

1.

  • In absence of atmosphere, the force that will act on the steroid is the force of gravity due to asteroid.
  • Gravitational force is a long range force acting always attractive in nature.
  • It is a contact-less field force which does not requires a medium.

Mathematically given as:

F=G.\frac{M_1.M_2}{R^2}

where:

G = gravitational constant

M_1\ \&\ M_2 are the mass of the two objects

R= radial distance between the two objects.

2.

The acceleration of the ball at the top height of the path is still under the influence of the gravity of the two masses so it will be equal to the acceleration due to gravity at the surface of the asteroid. Acceleration always remains constant.

You might be interested in
A roulette wheel with a 1.0m radius reaches a maximum angular speed of 18 rad/s before it stops 35 revolutions ( 220 rad ) after
Alex17521 [72]
Max ang. speed(u) = 18 rad/s
final ang. speed(v) = 0
ang. displacement(s) = 220 rad

ang. acceleration = (v^2 - u^2)/2s = -18^2 / 2*220 = -0.7364 rad/s^2

v = u +at
0 = 18 - 0.7364t
t = 18/0.7364
t = 24.44 seconds
4 0
2 years ago
What goes through evaporation
Olegator [25]
Water goes through evaporation.
6 0
3 years ago
Read 2 more answers
A parallel-plate air capacitor is made from two plates 0.190 m square, spaced 0.770 cm apart. It is connected to a 120 V battery
Naddik [55]

Answer:

aaksj

Explanation:

a) the capacitance is given of a plate capacitor is given by:

C = \epsilon_0*(A/d)

Where \epsilon_0 is a constant that represents the insulator between the plates (in this case air, \epsilon_0 = 8.84*10^(-12) F/m), A is the plate's area and d is the distance between the plates. So we have:

The plates are squares so their area is given by:

A = L^2 = 0.19^2 = 0.0361 m^2

C = 8.84*10^(-12)*(0.0361/0.0077) = 8.84*10^(-12) * 4.6883 = 41.444*10^(-12) F

b) The charge on the plates is given by the product of the capacitance by the voltage applied to it:

Q = C*V = 41.444*10^(-12)*120 = 4973.361 * 10^(-12) C = 4.973 * 10^(-9) C

c) The electric field on a capacitor is given by:

E = Q/(A*\epsilon_0) = [4.973*10^(-9)]/[0.0361*8.84*10^(-12)]

E = [4.973*10^(-9)]/[0.3191*10^(-12)] = 15.58*10^(3) V/m

d) The energy stored on the capacitor is given by:

W = 0.5*(C*V^2) = 0.5*[41.444*10^(-12) * (120)^2] = 298396.8*10^(-12) = 0.298 * 10 ^6 J

6 0
2 years ago
Read 2 more answers
Jaclyn plays singles for South's varsity tennis team. During the match against North, Jaclyn won the sudden death tiebreaker poi
Nataly [62]

Answer

given,

mass of ball, m = 57.5 g = 0.0575 kg

velocity of ball northward,v = 26.7 m/s

mass of racket, M = 331 g = 0.331 Kg

velocity of the ball after collision,v' = 29.5 m/s

a) momentum of ball before collision

   P₁ = m v

   P₁ = 0.0575 x 26.7

   P₁ = 1.535 kg.m/s

b) momentum of ball after collision

   P₂ = m v'

   P₂ = 0.0575 x (-29.5)

   P₂ = -1.696 kg.m/s

c) change in momentum

    Δ P = P₂ - P₁

    Δ P = -1.696 -1.535

    Δ P = -3.231 kg.m/s

d) using conservation of momentum

  initial speed of racket = 0 m/s

  M u + m v = Mu' + m v

  M x 0 + 0.0575 x 26.7 = 0.331 x u' + 0.0575 x (-29.5)

  0.331 u' = 3.232

     u' = 9.76 m/s

change in velocity of the racket is equal to 9.76 m/s

5 0
3 years ago
A ball is dropped from rest from a height h above the ground. another ball is thrown vertically upwards from the ground at the i
Darya [45]

The position of the first ball is

y_1=h-\dfrac g2t^2

while the position of the second ball, thrown with initial velocity v, is

y_2=vt-\dfrac g2t^2

The time it takes for the first ball to reach the halfway point satisfies

\dfrac h2=h-\dfrac g2t^2

\implies\dfrac h2=\dfrac g2t^2

\implies t=\sqrt{\dfrac hg}

We want the second ball to reach the same height at the same time, so that

\dfrac h2=v\sqrt{\dfrac hg}-\dfrac g2\left(\sqrt{\dfrac hg}\right)^2

\implies h=2v\sqrt{\dfrac hg}-g\left(\dfrac hg\right)

\implies h=v\sqrt{\dfrac hg}

\implies v=\sqrt{hg}

8 0
3 years ago
Other questions:
  • An x-ray beam with wavelength 0.240 nm is directed at a crystal. as the angle of incidence increases, you observe the first stro
    6·1 answer
  • A stretch spring has an elastic potential energy of 35 J when it is stretched 0.54m. What is the spring constant of the spring?
    15·1 answer
  • A uniform 190 g rod with length 43 cm rotates in a horizontal plane about a fixed, vertical, frictionless pin through its center
    10·1 answer
  • Tension is actually a force that tends to
    7·2 answers
  • The fact that desert sand is very hot in the day and very cold at night is evidence that sand has
    7·2 answers
  • HELP ASAP
    7·1 answer
  • A straight wire in a magnetic field experiences a force of 0.026 N when the current in the wire is 1.5 A. The current in the wir
    7·1 answer
  • A ball is thrown vertically upwards with a velocity of 20 m s −1 from the top of a multistorey building of 25 m high. How high w
    8·1 answer
  • Topic: Chapter 19: Some wiggle room
    8·1 answer
  • A 0.25-kilogram ball is observed to accelerate at 4,000 m/sec2 as it is hit with a bat.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!