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Nimfa-mama [501]
3 years ago
9

Without surfactant, _______.

Physics
1 answer:
Musya8 [376]3 years ago
5 0
B is the answer to the question
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Magnesium atomic no. = 24,25,26. These are the two elements which have same atomic no

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What are the frequencies of EM spectrum
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The EM spectrum has no limits.  Any frequency you can imagine
is the frequency of some electromagnetic radiation somewhere.


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2. For each of the listed parts of a power plant, make a selection to indicate in what
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Answer: Find the answer in the explanation

Explanation: Given the Roman numeral and the representation

I. part of a coal-fired power plant

II. part of a nuclear power plant

III. part of a coal-fired power plant and part of a nuclear power plant

a.) Boiler : I

b.) Combustion chamber: I

c.) Condenser: I

d.) Control rod: II

e.) Generator: III

f.) Turbine: III

Toward the end processes part of both coal fire and nuclear power, they both make use of turbine and generator to generate electricity.

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Let's say you go on a run and start to sweat because you are heating up.
Jobisdone [24]

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kinetic to thermal

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3 years ago
A ball is in free fall after being dropped. What willthe speed of the ball be after 2 seconds of free fall?
Mazyrski [523]

So, the speed of the ball after 2 seconds after free fall is <u>20 m/s</u>.

<h3>Introduction</h3>

Hi ! I'm Deva from Brainly Indonesia. In this material, we can call this event "Free Fall Motion". There are two conditions for free fall motion, namely falling (from top to bottom) and free (without initial velocity). Because the question only asks for the final velocity of the ball, in fact, we may use the formula for the relationship between acceleration and change in velocity and time. In general, this relationship can be expressed in the following equation :

\boxed{\sf{\bold{a = \frac{v_2 - v_1}{t}}}}

With the following conditions :

  • a = acceleration (m/s²)
  • \sf{v_2} = speed after some time (m/s)
  • \sf{v_1} = initial speed (m/s)
  • t = interval of time (s)

<h3>Problem Solving</h3>

We know that :

  • a = acceleration = 9,8 m/s² >> because the acceleration of a falling object is following the acceleration of gravity (g).
  • \sf{v_1} = initial speed = 0 m/s >> the keyword is free fall
  • t = interval of time = 2 s

What was asked :

  • \sf{v_2} = speed after some time = ... m/s

Step by step :

\sf{a = \frac{v_2 - v_1}{t}}

\sf{(a \times t) + v_1 = v_2}

\sf{(10 \times 2) + 0 = v_2}

\boxed{\sf{v_2 = 20 \: m/s}}

So, the speed of the ball after 2 seconds after free fall is 20 m/s.

8 0
2 years ago
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