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3 years ago

5. Did objects have to touch to interact? What causes this?

Physics

2 answers:

dimulka [17.4K]3 years ago

6 0

Answer:

★ For example, a useful analogy for explaining the Earth's gravity force is that the Earth can pull on objects without touching them just like a magnet can affect other objects without touching them. In Addition, the main notion to convey here is that forces can act at a distance with no perceivable substance in between.

Explanation:

Hope you have a great day :)

djverab [1.8K]3 years ago

5 0

Answer/Explanation

A useful analogy for explaining the Earth's gravity force is that the Earth can pull on objects without touching them just like a magnet can affect other objects without touching them. The main notion to convey here is that forces can act at a distance with no perceivable substance in between.

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Simplifying fractions<br>30 over 54

Veronika [31]

Answer:

5/9

Explanation:

First, find a common factor for 30 and 54.

30 and 54 can both be divided by 2.

30 divided by 2 = 15

54 divided by 2 = 27

So, your new fraction is 15/27.

However, don't stop there.

15 and 27 can both be divided by 3 as well.

15 divided by 3 = 5

27 divided by 3 = 9

So, your final answer is 5/9.

I hope this helps! :)

4 0

3 years ago

Read 2 more answers

What is the density of an object that has a mass of 10 g and a volume

Korolek [52]

2g/mL

Explanation:

Given parameters :

Mass = 10g

Volume = 5mL

Unknown:

Density of the object = ?

Solution:

Density is defined as the mass per unit volume of a body.

Density = $\frac{mass}{Volume}$

Now, input the values in the equation:

Density = $\frac{10}{5}$ = 2g/mL

Learn more:

Density brainly.com/question/5055270

#learnwithBrainly

7 0

3 years ago

A cylinder rotating about its axis with a constant angular acceleration of 1.6 rad/s 2 starts from rest at t = 0. At the instant

umka21 [38]

Answer:

a = 0.27 rad/s^2

Explanation:

First we will find the time t using the next equation:

θ = $\frac{1}{2}at^2$

where θ is the angle in radians and a is the angular aceleration. So:

0.4 = $\frac{1}{2}(1.6)t^2$

Solving for t:

t = 0.707s

Second, with that time, we will find the angular velocity w using the next equation:

w = at

where a is the angular aceleration, so:

w = (1.6)(0.707s)

w = 1.1312 rad/s

Now, the radial aceleration $a_r$ is calcualted as:

$a_r$ = $w^2r$

$a_r$ = $(1.1312)^2(0.13)$

$a_r$ = 0.166 rad/s^2

Additionally, the tangential aceleration $a_t$ is calculated as::

$a_t = ar$

$a_t = (1.6)(0.13)$

$a_t = 0.208 rad/s^2$

Finally, by pythagoras theorem, we find the total linear acceleration as:

$a = \sqrt{a_r^{2}+a_t^2 }$

$a = \sqrt{(0.208)^2+(0.166)^2 }$

a = 0.27 rad/s^2

4 0

3 years ago

What is the value of the composite constant (gmer2e), to be multiplied by the mass of the object mo in the equation above? expre

Bezzdna [24]

The solution would be like this for this specific problem:

F = (G Me Mo) / Re^2

F / Mo = (G Me) / Re^2

G = gravitational constant = 6.67384 * 10^-11 m3 kg-1 s-2

Me = 5.972 * 10^24 kg

Re^2 = (6.38 * 10^6)^2 m^2 = 40.7044 * 10^12 m^2 = 4.07044 * 10^13 m^2

G Me / Re^2 = (6.67384 * 10-11 * 5.972 * 10^24) / 4.0704 * 10^13 = 9.7196 m/s^2

9.7196 m/s^2 = acceleration due to Earth’s gravity

Therefore, the value of the composite constant (Gme / r^2e) that is to be multiplied by the mass of the object mo in the equation above is 9.7196 m/s^2.

8 0

3 years ago

Read 2 more answers

Describe the motion of an object:

Tamiku [17]

Answer:

A. Here object is moving with increasing velocity

B. Here the object is moving with decreasing velocity that is it is decelerating

C. Here the initial and final velocity are the same so the object moves at constant velocity

D. Here the object started from rest but reached a certain velocity with time so a non zero acceleration was attained

3 0

3 years ago