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kaheart [24]
3 years ago
11

Ethanethiol (; also called ethyl mercaptan) is commonly added to natural gas to provide the ""rotten egg"" smell of a gas leak.

The boiling point of ethanethiol is 35°C and its heat of vaporization is 27.5 kJ/mol. What is the entropy of vaporization for this substance?
Physics
1 answer:
Tju [1.3M]3 years ago
3 0

Answer:

S = 27500J / 308.15molK

Explanation:

Entropy measures the degree of disorganization of a system. It is measured in the entropy change that is equal to the heat exchanged divided by the temperature at which the process occurs.

S2-S1 = Q / T

S = entropy

Q = heat = 27.5 kJ / mol * 1000J / 1KJ = 27500J / mol

T = temperature = 35 + 273.15 = 308.15K

units = J / molK

S = 27500J / 308.15molK

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<em>Work</em><em> done</em><em> </em><em>=</em><em> </em><em>2</em><em>5</em><em>N</em><em>(</em><em>0</em><em>.</em><em>7</em><em>6</em><em>6</em><em>0</em><em>)</em><em> </em><em>×</em><em> </em><em>5</em><em>0</em><em>m</em>

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