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4 years ago

Classify the waves as longitudinal or transverse.

Physics

1 answer:

tresset_1 [31]4 years ago

8 0

Answer:

1. transverse

2. transverse

3. longitudinal

4. idk

Explanation:

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Think of a way you could demonstrate elastic force to a younger student. Describe the procedure you would follow and the materia

Soloha48 [4]

Answer:

I feel like to demonstrate you would use an elastic band as the material. You obviously have to put force in order to see how far it stretches. From this you can also find about its resistance and durability

Also you have to make sure the distance between the two hands are equal as you want an accurate result.

7 0

3 years ago

A simple pendulum has a period of 3.45 second, when the length of the pendulum is shortened by 1.0m, the period is 2.81 second c

den301095 [7]

Answer:

Original length = 2.97 m

Explanation:

Let the original length of the pendulum be 'L' m

Given:

Acceleration due to gravity (g) = 9.8 m/s²

Original time period of the pendulum (T) = 3.45 s

Now, the length is shortened by 1.0 m. So, the new length is 1 m less than the original length.

New length of the pendulum is, $L_1=L-1$

New time period of the pendulum is, $T_1=2.81\ s$

We know that, the time period of a simple pendulum of length 'L' is given as:

$T=2\pi\sqrt{\frac{L}{g}}$ -------------- (1)

So, for the new length, the time period is given as:

$T_1=2\pi\sqrt{\frac{L_1}{g}}$ ------------ (2)

Squaring both the equations and then dividing them, we get:

$\dfrac{T^2}{T_1^2}=\dfrac{(2\pi)^2\frac{L}{g}}{(2\pi)^2\frac{L_1}{g}}\\\\\\\dfrac{T^2}{T_1^2}=\dfrac{L}{L_1}\\\\\\L=\dfrac{T^2}{T_1^2}\times L_1$

Now, plug in the given values and calculate 'L'. This gives,

$L=\frac{3.45^2}{2.81^2}\times (L-1)\\\\L=1.507L-1.507\\\\L-1.507L=-1.507\\\\-0.507L=-1.507\\\\L=\frac{-1.507}{-0.507}=2.97\ m$

Therefore, the original length of the simple pendulum is 2.97 m

4 0

3 years ago

2. A rock is dropped from rest at the top of a 10 meter tall building. How much time does the rock

ivann1987 [24]

Answer:

1.4 seconds

Explanation:

here u= 0

v= ?

h= 10m

g= 9.8 m/ s*2

using 2as = v^2 - u ^2

2x9.8x10 = v^2 - 0

v^2 = 196

v = 14 m

time = v- u/ a

14 / 98

1.4 seconds

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3 years ago

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3 years ago

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