160 g of SO3 are needed to make 400 g of 49% H2SO4.
<h3>How many grams of SO3 are required to prepare 400 g of 49% H2SO4?</h3>
The equation of the reaction for the formation of H2SO4 from SO3 is given below as follows:
1 mole of SO3 produces 1 mole of H2SO4
Molar mass of SO3 = 80 g/mol
Molar mass of H2SO4 = 98 g/mol
80 g of SO3 are required to produce 98 og 100%H2SO4
mass of SO3 required to produce 400 g of 100 %H2SO4 = 80/98 × 400 = 326.5 g of SO3
Mass of SO3 required to produce 49% of 400 g H2SO4 = 326.5 × 49% = 160 g
Therefore, 160 g of SO3 are needed to make 400 g of 49% H2SO4.
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0.6 mol / L is the molarity of a solution prepared by dissolving 36. 0 g of NaOH in enough water to make 1. 50 l of solution.
The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another term for molarity.
The ratio employed to indicate the solution's concentration is called its molarity. Understanding a solution's molarity is important since it allows you to determine the actual concentration as well as whether the solution is diluted or concentrated.
Amount of NaOH = 36. 0 g
Amount of water = 1. 50 L
1 mol of NaOH = 40 g,
Moles of NaOH = 36. 0 / 40 g = 0.9 mol NaOH
Molarity of a solution = moles of solute / Liters of solution
Molarity of a solution = 0.9 / 1.50
Molarity of a solution = 0.6 mol / L
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There is no gravity and gravity pulls things down
