Whenever the forces applied to an object that is at rest are balanced, it will..l
1 answer:
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Answer:
1) The distance further it takes Peter to arrive at the Coffee shop than Mia is 1.24 km
2) Mia's average speed is 6.00 km/hour
Peter's average speed is 8.48 km/hour
4) Mia's average velocity = Peter's average velocity = 6.00 km/hour
Explanation:
The given information from the diagram are;
The distance Peter jogs from school to the flower shop = 2.00 km
The distance Peter jogs from the Flower shop to the Coffee shop = 2.24 km.
The distance Mia walks from school directly to the Coffee shop = 3.00 km
The time it takes both Peter and Mia to arrive at the coffee shop = 30 minutes = 0.5 hour
1) The total distance Peter travels from school to the Coffee shop = 2.00 km + 2.24 km = 4.24 km
The distance Mia travels from school to the Coffee shop = 3.00 km
The distance further it takes Peter to arrive at the Coffee shop than Mia = 4.24 km - 3.00 km = 1.24 km
The distance further it takes Peter to arrive at the Coffee shop than Mia = 1.24 km
2)
Mia's average speed = 6.00 km/hour
Peter's average speed = 8.48 km/hour
4)
The displacement from the School to the Coffee shop is 3.00 km for both Mia and Peter
The time it takes both Peter and Mia to arrive at the Coffee shop from the school is 30 minutes = 0.5 hour
Mia's average velocity = 6.00 km/hour
Therefore, Peter's average velocity is also = 6.00 km/hour
Answer:
F = 233.52 N, θ' = 351.41º
Explanation:
In this exercise we must find the net force applied on the donkey.
For this we use Newton's second law, where we create a reference frame with the horizontal x axis
let's decompose the forces
Jack
= 80.5 N
Jill
cos 45 = F_{2x} / F₂2
sin 45 = F_{2y} / F₂2
F_{2x} = F₂ cos 45
F_{2y} = F₂ sin 45
F_{2x} = 81.7 cos 45 = 57.77 N
F_{2y} = 81.7 sin 45 = 57.77 N
Jane
cos (270 + 45) = F_{3x} / F₃3
sin 315 = F_{3y} / F₃
F_{3x} = 131 cos 315 = 92.63 N
F_{3y} = 131 sin 315 = -92.63 N
the force can be found in each axis
X axis
F_{x} = F_{1x} + F_{2x} + F_{3x}
F_{x} = 80.5 +57.77 + 92.63
F_{x} = 230.9 N
Axis y
F_{y} = F_{1y} + F_{2y} + F_{3y}
F_{y} = 0 + 57.77 -92.63
F_{y} = -34.86 N
we can give the result in two ways
a) F = (230.9 i ^ - 34.86 j ^) N
b) in the form of module and angle
we use the Pythagorean theorem
F = √(Fₓ² + F_{y}²
F = √(230.9² + 34.86²)
F = 233.52 N
let's use trigonometry for the angle
tan θ =
θ = tan⁻¹ (\frac{F_y}{F_x} })
θ = tan⁻¹ (-34.86 / 230.9)
θ = -8.59º
if we measure this angle from the positive side of the x-axis counterclockwise
θ' = 360 -θ
θ‘= 360- 8.59
θ' = 351.41º