Answer:
The molecular weight of CO is 28.01g/mole.
Answer:
D
Explanation:
i think its D because 3p33d74s2
<span>We use the formula PV = nRT. P = 758 torr = 0.997 atm. V = 3.50 L. T = 35.6 C = 308.15 K. R = 0.0821. Rearranging the equation gives up n = PV/Rt and we get .0138 moles of butane. Mass of 0.0138 moles of butane = .0138 x 58.12 = 8.02g.</span>
Answer:
0.015% and 0.012%
Explanation:
using simultaneous equation
On point? Do you have any options?