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DENIUS [597]
3 years ago
7

How can you tell that a chemical change has occurred?

Chemistry
1 answer:
Alik [6]3 years ago
5 0

A. The products of the change are different from the starting

substances.

<u>Explanation:</u>

Whenever there is a physical change it may just affect the phase change but the properties remains the same. Whenever there is an occurrence of a chemical change, it was indicated by some of these things such as,

  • The products are exactly different from the products.
  • Chemical properties of these reactants are entirely different from that of the products.
  • Chemical composition as well as the physical properties of the reactants and the products will change
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A balloon filled with helium gas at 20 °C occupies 4.91 L at 1.00 atm. The balloon is immersed in liquid nitrogen at -196°C, rai
Sauron [17]

Answer:

(A)0.25L

Explanation:

By combination of Boyle's law and Charles law to obtain the general gas equation, we have:

P1V1/T1=P2V2/T2

P1=Inital pressure=1.00 atm

V1=Inital volume=4.91L

T1=Initial temperature=20°C=20+273=293Kelvin

P2=Final pressure=5.2atm

T2=Final temperature=(-196+273K)=77K

V2= final volume=?

by making V2 the subject of the above general gas equation

we have V2=P1V1T2/P2T1

=1×4.91×77/5.2×293

=0.248L

7 0
3 years ago
Is a 10 carat gold ring considered a pure substance?
Fynjy0 [20]
It is a pure substance
6 0
3 years ago
Read 2 more answers
What is the pOH of 0.50 molar H3BO3?
Crazy boy [7]

<u>Answer:</u>

<em>A. 10.25</em>

<em></em>

<u>Explanation:</u>

Pkb =4.77

So pka = 14 - pka = 9.23

Ka =10^{-pka}

H_3 BO_3 (aq)+ H_2 O(l) H_2 BO_3^- (aq)+H_3 O^+ (aq)

Initial                0.50M                                 0                                 0

Change                  -x                                 +x                               +x

Equilibrium    0.50M-x                               +x                               +x

Ka =\frac {((x)(x))}{(0.50M-x)}

5.88\times10^{-10}= \frac {x^2}{(0.50M-x)}

(-x is neglected) so we get

5.88\times10^{-10}\times0.50=x^2\\\\x^2=2.94\times10^{-10}

x=\sqrt{x^2}=1.72\times10^{-5} M=H^3 O^{+}

pH=-log[H^3 O^+]\\\\pH=-log[1.72\times10^{-5}]\\\\pH=4.76

pOH = 14 - pH

= 14 - 4.76

pOH = 9.24 is the answer

Option A - 10.25 is the answer which is close to 9.24

4 0
3 years ago
Find the atomicity of water.​
Flauer [41]
One molecule of water contains two atoms of hydrogen and one atom of oxygen, the atomicity of water is three.
4 0
3 years ago
What is the volume if density of gold is 19.3g/ml and sand is 2.3g/ml with 1L of volume?
malfutka [58]
Use the volume and density of the gold statue to calculate the mass of the statue.
density = mass / volume, or rearranged, mass = density • volume
Convert the volume of the statue from L to mL so volume unit agrees with density unit
mass of statue = 19.3 g/mL • 1000 mL = 19 300 g

Mass of sand must be same as the mass of the statue, 19 300 g
Use the mass and density of the sand to calculate the volume of sand needed
density = mass / volume, or rearranged, volume = mass / density
volume of sand needed = 19 300 g / 23 g/mL = 8391 mL or 8.391 L

1b
Calculate the density of the statue from the measured mass and volume. If the calculated density agrees with the known density of gold, then the statue is made from pure gold.

density = mass / volume
Convert the mass from kg to g as you want the answer in g/mL so you can compare it to the reference value of gold given in the problem. 16.5 kg • 1000 g / 1 kg = 16 500 g
density of the statue = 16 500 g / 954 mL = 17.3 g/mL

Since this density, 17.3 g/mL is significantly different from the known density of gold, 19.3 g/mL, the statue cannot be made of pure gold. The gold was mixed with a less dense metal.
3 0
3 years ago
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