Answer:
Will experience a force due to electric field.
Explanation:
- When a free negative charge is released in an electric field it experiences a force due to the electric field in a direction opposite to the direction of the magnetic field.
According to Coulomb's law this force is mathematically given as:

and, electric field due to a charge is given as:

where:
permittivity of free space
q = magnitude of charge
r = radial distance from the charge
The distance that is traveled by the astronaut given that the motion is free-fall can be calculated through the equation,
d = Vot + 0.5at²
where d is the distance, Vo is the initial velocity, t is the time, and a is the acceleration. Substituting the known,
6 = (0 m/s)(2.7 s) + 0.5(a)(2.7 s)²
Determining the value of a,
a = 1.646 m/s²
ANSWER: 1.646 m/s²
Answer:
292.3254055 W/m²
469.26267 V/m

Explanation:
P = Power of bulb = 90 W
d = Diameter of bulb = 7 cm
r = Radius = 
= Permittivity of free space = 
c = Speed of light = 
The intensity is given by

5% of this energy goes to the visible light so the intensity is

The visible light intensity at the surface of the bulb is 292.3254055 W/m²
Energy density of the wave is

Energy density is also given by

The amplitude of the electric field at this surface is 469.26267 V/m
Amplitude of a magnetic field is given by

The amplitude of the magnetic field at this surface is 
22N to the right and 13N to the left
Forces are in opposite directions so you subtract the bigger force from the smaller force
Magnitude of force= 22N -13N
= 9N
net force direction is to the right
Answer:
v0 = 24.42 m/s (Approx)
Explanation:
Given:
Increase in frequency = 7.1% =
Computation:
Assume n = 100%
n1 = [(v+v0)/(v+v1)]n
[100 + 7.1] = [(344+v0)/(344+0)]100
107.1 = [(344+v0)/(344)]100
v0 = 24.42 m/s (Approx)