Which one of the following accurately describes a proper use of eyeglasses?

Physics

2 answers:

erastova [34]3 years ago

6 0

Answer:

B. Using diverging lenses to help a nearsighted person by moving the image from in front of the retina to the retina

Explanation:

To see an object, the light rays coming from the object must converge on the retina. Nearsightedness or myopia is the condition where the rays get converged before (or in front of) the retina. Thus the image on the retina will not be clear and the observer will not be able to see nearby objects.

To correct this we use a diverging lens which shifts the converging point or focus to the retina.

stiks02 [169]3 years ago

5 0

The statement that accurately describes a proper use of eyeglasses is statement A. Using converging lenses to help a nearsighted person by moving the image from in front of the retina to the retina.

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You push your couch a distance of 3.9 m across the living room floor with a horizontal force of 220.0 n. the force of friction i

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The general formula to calculate the work is:

$W=Fd \cos \theta$

where F is the force, d is the displacement of the couch, and $\theta$ is the angle between the direction of the force and the displacement. Let's apply this formula to the different parts of the problem.

(a) Work done by you: in this case, the force applied is parallel to the displacement of the couch, so $\theta=0^{\circ}$ and $\cos \theta=1$ , therefore the work is just equal to the product between the horizontal force you apply to push the couch and the distance the couch has been moved:

$W=Fd=(220.0 N)(3.9 m)=858 J$

(b) work done by the frictional force: the frictional force has opposite direction to the displacement, therefore $\theta=180^{\circ}$ and $\cos \theta=-1$ . Therefore, we must include a negative sign when we calculate the work done by the frictional force:

$W=-Fd=-(144.0 N)(3.9 m)=-561.6 J$

(c) The work done by gravity is zero. In fact, gravity (which points downwards) is perpendicular to the displacement of the couch (which is horizontal), therefore $\theta=90^{\circ}$ and $\cos \theta=0$ : this means