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3 years ago

Which pair of scientific fields would be most useful in understanding how the

Chemistry

1 answer:

wariber [46]3 years ago

8 0

Answer:

chemistry and physics

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What group of substances does this substance belong to?

HACTEHA [7]

In comparison see it is very easy in goolge

4 0

2 years ago

What is the most common salt found in ocean water?

zhannawk [14.2K]

Hello.

The answer i believe would be sodium.

Have a great day.

3 0

3 years ago

PLEASE HELP!!!

Inga [223]

Answer:

$d=1.5\ g/cm^3$

Explanation:

Given that,

The mass of the rock, m = 15 g

The volume of the rock, V = 10 cm³

We need to find the density of the rock. The density of an object is equal to the mass per unit volume such that,

$d=\dfrac{m}{V}\\\\d=\dfrac{15\ g}{10\ cm^3}\\\\d=1.5\ g/cm^3$

So, the density of the rock is equal to $1.5\ g/cm^3$ .

3 0

3 years ago

What does the nucleus do

mel-nik [20]

<span>The nucleus is the organelle present in eukaryotic cells with the main function in the control of all cell activities and maintaining the gene integrity. Namely, it contains the genetic material of the cell in the form of chromosomes (DNA molecules in complex with proteins). It is enclosed by the nuclear membrane which regulates the movement of proteins and RNA in and out of the nucleus.</span>

4 0

3 years ago

A compound is found to contain 64.80 % carbon, 13.62 % hydrogen, and 21.58 % oxygen by weight. What is the empirical formula for

insens350 [35]

Answer:

Empirical formula is C₄H₁₀O

Explanation:

Values for C, H and O are determined as centesimal composition.

64.80 g of C in 100g of compound

13.62g of H in 100 g of compound

21.58 g of O in 100 g of compound.

We convert the mass to moles:

64.80 g . 1mol/ 12g = 5.4 moles of C

13.62 g . 1 mol /1g = 13.62 moles of H

21.58 g . 1 mol/16g = 1.35 moles of O

We pick the lowest value and we divide:

5.4 moles of C / 1.35 = 4 C

13.62 moles of H / 1.35 = 10 H

1.35 moles of O / 1.35 = 1 O

Empirical formula is C₄H₁₀O, it can be the diethyl ether.

We confirm, the excersise is well done.

Molar mass = 74g/mol

74 g of compound we have (12 . 4)g of C

In 100 g of compound we may have (100 . 48) / 74 = 64.8 g

5 0

2 years ago