k = 1/2 × m × v^2
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1. k = 1/2 × 60 × ( 10 )^2
k = 30 × 100
k = 3000 j
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2. k = 1/2 × 60 × ( 9 )^2
k = 30 × 81
k = 2430 j
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3. k = 1/2 × 60 × ( 4 )^2
k = 30 × 16
k = 480 j
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4. k = 1/2 × 60 × ( 6 )^2
k = 30 × 36
k = 1080 j
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5. k = 1/2 × 60 × ( 0 ) ^2
k = 30 × 0
k = 0 j
She say give tow points and write the equation of the line with the two give points (1,5) and (-3,-5 )
Answer:
The speed of the two cars after coupling is 0.46 m/s.
Explanation:
It is given that,
Mass of car 1, m₁ = 15,000 kg
Mass of car 2, m₂ = 50,000 kg
Speed of car 1, u₁ = 2 m/s
Initial speed of car 2, u₂ = 0
Let V is the speed of the two cars after coupling. It is the case of inelastic collision. Applying the conservation of momentum as :
V = 0.46 m/s
So, the speed of the two cars after coupling is 0.46 m/s. Hence, this is the required solution.
The answer is potential for this question
1cathode rays plural : the high-speed electrons emitted in a stream from the heated cathode of a vacuum tube
2: a stream of electrons emitted from the cathode of a vacuum tube —usually used in plural
