QPOE Files
The x-ray data are stored in QPOE files (Quick Position-Ordered Events, *.qp) rather than image arrays. These are lists of photons identified by several quantities, including the position on the detector, pulse height, and arrival time. Note that, unlike IRAF images, QPOE files have no associated header file, and are always stored in the current directory, unless explicitly specified otherwise. Non-PROS IRAF tasks can also access QPOE data files in place of image arrays.
Answer:
1.20 M
Explanation:
Convert grams of Na₂CO₃ to moles. (50.84 g)/(105.99 g/mol) = 0.4797 mol
Molarity is (moles of solute)/(liters of solvent) = (0.4797 mol)/(0.400 L) = 1.20 M
To get the number of gold atoms, you have to divide the mass of the gold by the mass of the gold atom. It follows this simple equation
.
Let x be the number of gold atoms. Plug in the values to a calculator.
x =
Both have the same units so the unit gram(g) can be cancelled.
x then would be equal to 1.53x10^22. So there are 1.53x10^22 atoms of gold in 5 g of gold
Answer:
D. 5.6 g/cm^3
Explanation:
On the average seismic velocity increases with increase in depth due higher the pressure and more compaction
sand and shales in the Niger Delta Basin density–velocity relationship is
P = 0.31×V^0.25
A derivation of the original Gardner equation to calculate the average densities for sands and shales in wells.
ρ = α ×V^β
where
ρ = bulk density in g/cm3,
V = P-wave velocity,
α = 0.31 for V (m/s) and 0.23 for V(ft/s) and
β = 0.25.
Such that
ρ = 0.31 ×V^0.25
So the fastest seismic velocity will be in the densest material which is D. 5.6 g/cm3
Answer:
mass and distance
Explanation:
The strength of this force depends on the <u>mass</u>
of each object and
the <u>distance</u>
between them.
