Question

The table below shows data of sprints of animals that traveled 75 meters. At each distance marker, the animals' times were recorded. Which animal moves with accelerated motion?

Answer 1

Answer:

i think its animal 4

Explanation:

Answer 2

Answer:

Animal 1

Explanation:

By the definition we know:

$acceleration= \frac{change\,\,in\,\,speed}{time\,\,taken}$

From the given data table we calculate the speed of each animal at the given distance points.

$speed=\frac{distance}{time}$

Animal 1:

after 25 meters:

$speed=\frac{25}{3}$

$speed=8.33 \,m.s^{-1}$

after 50 meters:

$speed=\frac{50}{5}$

$speed=10 \,m.s^{-1}$

enough to prove that there exists acceleration  because of  change in speed with time.

Animal 2:

after 25 meters:

$speed=\frac{25}{4}$

$speed=6.25 \,m.s^{-1}$

after 50 meters:

$speed=\frac{50}{8}$

$speed=6.25 \,m.s^{-1}$

after 75 meters:

$speed=\frac{75}{12}$

$speed=6.25 \,m.s^{-1}$

has constant speed, hence no acceleration.

Animal 3:

after 25 meters:

$speed=\frac{25}{3}$

$speed=8.33 \,m.s^{-1}$

after 50 meters:

$speed=\frac{50}{6}$

$speed=8.33 \,m.s^{-1}$

after 75 meters:

$speed=\frac{75}{9}$

$speed=8.33 \,m.s^{-1}$

has constant speed, hence no acceleration.

Animal 4:

after 25 meters:

$speed=\frac{25}{10}$

$speed=2.5 \,m.s^{-1}$

after 50 meters:

$speed=\frac{50}{20}$

$speed=2.5 \,m.s^{-1}$

after 75 meters:

$speed=\frac{75}{30}$

$speed=2.5 \,m.s^{-1}$

has constant speed, hence no acceleration.