The table below shows data of sprints of animals that traveled 75 meters. At each distance marker, the animals' times were recor
ded. Which animal moves with accelerated motion?
2 answers:
Answer:
Animal 1
Explanation:
By the definition we know:
From the given data table we calculate the speed of each animal at the given distance points.
Animal 1:
after 25 meters:
after 50 meters:
enough to prove that there exists acceleration because of change in speed with time.
Animal 2:
after 25 meters:
after 50 meters:
after 75 meters:
has constant speed, hence no acceleration.
Animal 3:
after 25 meters:
after 50 meters:
after 75 meters:
has constant speed, hence no acceleration.
Animal 4:
after 25 meters:
after 50 meters:
after 75 meters:
has constant speed, hence no acceleration.
You might be interested in
Answer:
The magnitude of the charge on each sphere is 0.135 μC
Explanation:
Given that,
Mass = 1.0
Distance = 2.0 cm
Acceleration = 414 m/s²
We need to calculate the magnitude of charge
Using newton's second law
Put the value of F
Put the value into the formula
Hence, The magnitude of the charge on each sphere is 0.135μC.
1) In a circular motion, the angular displacement 
is given by
where S is the arc length and r is the radius. The problem says that the truck drove for 2600 m, so this corresponds to the total arc length covered by the tire:
. Using the information about the radius, 
, we find the total angular displacement:
2) If we put larger tires, with radius
, the angular displacement will be smaller. We can see this by using the same formula. In fact, this time we have:
where S is the arc length and r is the radius. The problem says that the truck drove for 2600 m, so this corresponds to the total arc length covered by the tire:
2) If we put larger tires, with radius