Answer:
T1 = 625.54 K
Explanation:
We are given;
T_α = Tsur = 25°C = 298K
h = 20 W/m².K,
L = 0.15 m
K = 1.2 W/m.K
ε = 0.8
Ts = T2 = 100°C = 373K
T1 = ?
Assumption:
-Steady- state condition
-One- dimensional conduction
-No uniform heat generation
-Constant properties
From Energy balance equation;
E°in - E°out = 0
Thus,
q"cond – q"conv – q"rad = 0
K[(T1 - T2)/L] - h(Ts-T_α) - εσ (Ts⁴ – Tsur⁴)
Where σ is Stephan-Boltzmann constant and has a value of 5.67 x 10^(-8)
Thus;
K[(T1 - T2)/L] - h(Ts-T_α) - εσ (Ts⁴ – Tsur⁴) = 1.2[(T1 - 373)/0.15] - 20(373 - 298] - 0.8x5.67x10^(-8)[373⁴ - 298⁴] = 0
This gives;
(8T1 - 2984) - (1500) - 520.31 = 0
8T1 = 2984 + 1500 + 520.31
8T1 = 5004.31
T1 = 5004.31/8
T1 = 625.54 K
Answer:
ICC
Explanation:
The International Building Code (IBC) is a model building code developed by the International Code Council (ICC). It has been adopted for use as a base code standard by most jurisdictions in the United States.
Answer:
Flow rate is 
Explanation:
Given information
Density of oil, 
kinematic viscosity, 
Diameter of pipe, D= 5 mm= 0.005 m
Length of pipe, L=40 m
Height of liquid, h= 3 m
Volume flow rate for horizontal pipe will be given by
where 
is dynamic viscosity and 
is pressure drop
At the bottom of the tank, pressure is given by
Since at the top pressure is zero, therefore change in pressure a difference between the pressure at the bottom and the top. It implies that change in pressure is still 
Dynamic viscosity, 
Now the volume flow rate will be
Proof of flow being laminar
The velocity of flow is given by
Reynolds number, 
Since the Reynolds number is less than 2300, the flow is laminar and the assumption is correct.
Answer:
D. Measure the voltage on the conductor with a known good meter
Explanation:
Answer:
Explanation:
Primary combustion where carbon monoxide (CO) and free hydrogen (H) are produced, and the secondary combustion where water vapor (H2O) and carbon dioxide (CO2) are formed.
