What are the nine Historical periods?

Introduction to gear and gear ratios: If you have two gears of the same size does the output speed increase, decrease, or remain

creativ13 [48]

Answer:

remain the same constant

Explanation:

if a small gear is making 5 rpm turning a big gear thats making 1 rpm the bug gear is making lots of torque but if its going the opposite way its much harder to turn the big gear 1 rpm just to make the little gear do 5 rpm and it makes way less torque if thre both the same size there ging to stay the same speed

4 0

3 years ago

Limestone scrubbing is used to remove SO2 in a flue gas desulfurization (FGD) system. Relevant reactions are given below. A lime

lord [1]

Answer:

hello some data related to your question is missing attached below is the missing data

answer : 63700 Ib/hr

Explanation:

Given data :

Limestone mix : consists of 94% CaCO3 and 6% inert material

Actual feed rate = 36,000 Ib/hr

SO2 in flue gas = 20,314 Ib/hr

FGD efficiency = 97%

resulting sludge contains 58% solids

<u>Calculate the Total sludge production rate </u>

First : determine SO2 removed in sludge

= 0.97 * 20314

= 19704.58 Ib/hr

next : moles of SO2 removed

= 19704.58 / 64 Ib/ Ib mol

= 307.88 Ib mol / hr

also moles of CaSO3 produced = 307.88 Ib mol / hr

mass of CaSO3 = 307.88 * 120 = 36946.09 Ib/hr

Therefore Total sludge production rate

= 36946.09 / 0.58

= 63700.15 Ib/hr

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7 0

2 years ago

g In the above water treatment facility, chemical concentration (mg/gal) within the tank can be considered uniform. The initial

vlada-n [284]

Answer:

0.05 mg / gallon

Explanation:

mass of chemecila coming in per minute = 50*10 = 500 mg/min

at a time t min , M = mass of chemical = 500*t mg

conecntartion of chemecal = 500t/10000 = 0.05 mg / gallon

8 0

3 years ago

A horizontal channel of height H has two fluids of different viscosities and densities flowing because of a pressure gradient dp

cricket20 [7]

Answer:

Given that;

Jello there, see explanstion for step by step solving.

A horizontal channel of height H has two fluids of different viscosities and densities flowing because of a pressure gradient dp/dx1. Find the velocity profiles of two fluids if the height of the flat interface is ha.

Explanation:

A horizontal channel of height H has two fluids of different viscosities and densities flowing because of a pressure gradient dp/dx1. Find the velocity profiles of two fluids if the height of the flat interface is ha.

See attachment for more clearity

6 0

3 years ago

A budding electronics hobbyist wants to make a simple 1.0-nF capacitor for tuning her crystal radio, using two sheets of aluminu

bazaltina [42]

Answer:

a. 8 sheets of paper is needed between her plates to get the proper capacitance

b. Area of Aluminum Foil needed = 0.45m²

c. To keep a 1.0-nF, a larger area of Teflon is required.

Explanation:

a.

First, we need to calculate the distance between two plates.

This is given by

d = Kε0A/C

Where

K = 3

ε0 = Physical Constant = 8.854 * 10^-12 C²/Nm²

A = Area = 22 * 28 = 616cm² = 0.0616m²

C = 1.0-nF = 1 * 10^-12F

So, d = (3 * 8.854 * 10^-12 C²/Nm² * 0.0616) / (1 * 10^-12F)

d = 1.64 * 10^-3m

d = 1.64mm

Now, that the distance has been solved.

The Number of Sheets, N is given by

N = d/d,sheet where d, sheet =the sheet thickness = 0.2mm

N = 1.64/0.2

N = 8.2

N = 8 sheets --- Approximated

b.

Here, she's changed the diameter of the sheets to 12mm

Well make use of the formula in (a) above

Using d = Kε0A/C

Where

d = 12 * 10^-3m

Other constraints remain unchanged

Make A the subject of formula

A = dC/Kε0

A = (12 * 10^-3m * 1 * 10^-12F)/(3 * 8.854 * 10^-12 C²/Nm²)

A= 0.45m²

c. From (b) above

A ∝ 1/K

As the dielectric constant increase, the area decreases

The dielectric constant of a Teflon is 2.1

This means that if she used a Teflon instead, the area will be larger.

So, to keep a 1.0-nF, a larger area of Teflon is required.

7 0

3 years ago