Answer:
percentage change in volume is 2.60%
water level rise is 4.138 mm
Explanation:
given data
volume of water V = 500 L
temperature T1 = 20°C
temperature T2 = 80°C
vat diameter = 2 m
to find out
percentage change in volume and how much water level rise
solution
we will apply here bulk modulus equation that is ratio of change in pressure to rate of change of volume to change of pressure
and we know that is also in term of change in density also
so
E = ................1
And ............2
here ρ is density
and we know ρ for 20°C = 998 kg/m³
and ρ for 80°C = 972 kg/m³
so from equation 2 put all value
dV = 0.0130 m³
so now % change in volume will be
dV % = × 100
dV % = × 100
dV % = 2.60 %
so percentage change in volume is 2.60%
and
initial volume v1 = ................3
final volume v2 = ................4
now from equation 3 and 4 , subtract v1 by v2
v2 - v1 =
dV =
put here all value
0.0130 =
dl = 0.004138 m
so water level rise is 4.138 mm
Answer:
infinite
Explanation:
The tangent of the angle the arm makes with the vertical will be the ratio of the centripetal acceleration to the acceleration due to gravity on the center of mass of the arm. The angle can only be 90° (fully-open arms) if that ratio is infinite.
The speed must be infinite for the arms to be fully open.
Answer:
repeated?
Explanation:
not really sure what type of answer choices you have
Answer:
All Brake lights are dimmer than normal because high resistance in the brake switch could be the cause according to Technician B.
Explanation:
According to Technician A
When the bulb is faulty then no current will flow through bulb and it will be open circuit.So no light will produce in bulb .
According to Technician B
When a high resistance inserted in series circuit the voltage across each resistance is reduced and this cause the light glow dimly.
Formula of resistance in series circuit
Rt=r1+r2+r3......
Answer:
elongation of the brass rod is 0.01956 mm
Explanation:
given data
length = 5 cm = 50 mm
diameter = 4.50 mm
Young's modulus = 98.0 GPa
load = 610 N
to find out
what will be the elongation of the brass rod in mm
solution
we know here change in length formula that is express as
δ = ................1
here δ is change in length and P is applied load and A id cross section area and E is Young's modulus and L is length
so all value in equation 1
δ =
δ =
δ = 0.01956 mm
so elongation of the brass rod is 0.01956 mm