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zaharov [31]
3 years ago
5

How is the earth a cracked hard boiled egg

Physics
1 answer:
xz_007 [3.2K]3 years ago
6 0

Answer:

the earth isn't a cracked hard boiled egg, but I'd guess they mean layers. A thin shell/crust and the yolk and whites of the egg represent layers of the earth

Explanation:

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What is the resistance of a 3.5m copper wire that has a cross-sectional area of 5.26 x 10-6 m2?
mestny [16]

R=ρ\frac{L}{A}

Where, R is resistance

ρ is resistivity,

L is length and

A is cross sectional area

Given, L= 3.5m

A=5.26 x 10⁻⁶ m²

ρ=1.68×10⁻⁸ ohms m

∴ R= \frac{(1.68)(3.5)}{5.26*100}

⇒ R=1.11×10⁻² ohms


3 0
3 years ago
Read 2 more answers
Do magnets work through glass?
Harrizon [31]
Yes but the thicker the glass the stronger the magnet has to be
7 0
3 years ago
The velocity of a free falling ball at different time intervals on unknown planet is shown in Figure 1.24.
dsp73

Answer:

a1 = (V2 - V1) / 1 s = 3.75 m/s^2

a2 = (V2 - V1) / (t2 - t1) = (7.5 - 3.75) / 1 s = 3.75 m/s^2

a3 = (V2 - V1) / (t2 - t1) = (7.5 - 3.75) / 1 s = 3.75 m/s^2

A) a = (a1 + a2 + a3) / 3 = 3.75 m/s^2

v = a (t2 - t1)

B) after    1 sec    v = 3.75 m / sec^2 * 1 sec = 3.75 m/s

    after   2 sec     v = v0 + a t = 3.75 m/s + 3.75 m/s^2 * 1 s = 7.5 m/s

C)  The velocity increases proportionaly to the time

D) One factor depends on the variation of the acceleration due to gravity because of different positions of measurement (on earth)

A much larger factor is due to air resisance of the air on the falling object

4 0
2 years ago
You push on the top edge of a 1.8 m tall solid circular cylinder of iron which is 4.00 cm in diameter. You push with a horizonta
Citrus2011 [14]

Answer:

\triangle x=3.2*10^-^5 m

Explanation:

From the question we are told that

Height of circular cylinder is h= 1.8m

Diameter of cylinderD=4cm=>0.04m

Horizontal Force  F=900N

Y = 10.0 *10^1^0 N/m^2 \\B = 9.0 * 10^1^0 N/m^2\\S = 4.0 * 10^1^0 N/m^2\\

Generally the formula for shear modulus is mathematically represented by

G=\frac{\tau}{\gamma}

Where

G=Shear modulus\\\tau= shear\ stress\\\gamma=shear strain

G=\frac{F/A}{\triangle x/L}

G=\frac{900/\pi r^2}{\triangle x/1.8}

4.0*10^1^0=\frac{900/\pi r^2}{\triangle x/1.8}

4.0*10^1^0=\frac{900}{\pi r^2}  *\frac{1.8}{\triangle x}

{\triangle x} =\frac{1620}{\pi r^2* 4.0*10^1^0}

\triangle x=3.2*10^-^5 m

5 0
3 years ago
Compare convergent plate boundaries that have the same density to convergent plate boundaries with different densities.
andrey2020 [161]

Answer:

If the two plates are of equal density, they usually push up against each other, forming a mountain chain. If they are of unequal density, one plate usually sinks beneath the other in a subduction zone. Hope this helps!

Explanation:

4 0
4 years ago
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