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BartSMP [9]
3 years ago
9

The melting point of copper is 1084 Celsius. How does the energy of the particles in a certain amount of liquid copper compare t

o the energy of the molecules in the same amount of liquid water? Why?
Chemistry
1 answer:
matrenka [14]3 years ago
4 0
The melting point of the solid form of water, which is ice, is 0°C. When we convert both temperatures to kelvin by adding 273 to each we get the melting point of copper as 1357K and that of ice is 273K. Then, dividing the melting point of copper by the melting point of ice, both in absolute temperature scale. The answer would be 4.97. Thus, the energy of molecules of copper is approximately {five} times compared to that of water
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This question can be simply solved by using heat formula,
    Q = mCΔT

Q = heat energy (J)
m = Mass (kg)
C = Specific heat capacity (J / kg K)
ΔT = Temperature change (K)

when water freezes, it produces ice at 0°C (273 K)
hence the temperature change is 25 K (298 K - 273 K)
C for water is 4186 J / kg K or 4.186 J / g K
By applying the equation,
 Q = 456 g x 4.186 J / g K x 25 K
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hence 47.72 kJ of heat energy should be removed.
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The answer is "Option B"

Explanation:

From the query, the following knowledge is derived:  

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