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marta [7]
3 years ago
7

if 500 mL of hydrogen are collected over water at 20 degrees celsius and 18.6psi, what will the volume of the dry gas be at STP

Chemistry
1 answer:
kifflom [539]3 years ago
6 0

Answer:

76

Explanation:

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In the simulation, open the Micro mode, then select solutions indicated below from the dropdown above the beaker in the simulati
Levart [38]

Explanation:

It is known that when pH of a substance is more than 7 then the substance is considered basic in nature. When pH of a substance is less than 7 then the substance is considered acidic in nature.

And, when the pH of a substance is equal to 7 then it is considered neutral in nature.

The pH of given substances are as follows.

Coffee = 5.0

Orange Juice = 3.5

Milk = 6.5

Soda pop = 2.5

Battery acid = 1.0

As battery acid as very low pH therefore, it is highly acidic in nature.

Thus, we can conclude that given acids are arranged in increasing order of acidity as follows.

          Milk < Coffee < Orange juice < Soda pop < Battery acid

8 0
3 years ago
Which of the following correctly labels the solute and solvent in a solution of ocean water?
DanielleElmas [232]

Hello there!

The solute is salt, and the solvent is water. So the answer is #1.

PS. Can I have Brainliest?

8 0
3 years ago
2CuO+2NH3------ 3Cu + 3H2O+ N2. Given that the relative molecular mass of copper oxide is 80, what volume of ammonia is required
Pani-rosa [81]

Volume of Ammonia(NH₃) = 22.4 L

<h3>Further explanation</h3>

Given

Reaction

3CuO+2NH₃⇒ 3Cu + 3H₂O+ N₂

<em>In the problem, the CuO coefficient should be 3 not 2</em>

M CuO = 80

mass CuO = 120 g

Required

The volume of NH₃

Solution

mol CuO :

\tt mol=\dfrac{mass}{M}\\\\mol=\frac{120}{80}\\\\mol=1.5

From the equation, mol ratio CuO : NH₃ = 3 : 2, so mol NH₃=

\tt \dfrac{2}{3}\times 1.5=1~mol

Assume at STP(0 °C, 1 atm) ⇒1 mol = 22.4 L, then volume of NH₃=22.4 L

4 0
3 years ago
In which isine is the strong nuclear force na strong enough to balance destuetatic forces between Gond?
romanna [79]

Answer:

neon 21 ang sagot diyan

Explanation:

iyan ang sagot ko its a frank hindi yan ang sagot ko

5 0
3 years ago
If your sample of vinegar is approximately 4.76% (w/w), what volume should you use so that approximately 40 mL of 0.1 M NaOH is
Ronch [10]

Based on the concentrations given, the volume of vinegar required is 5.04 mL.

<h3>What is the concentration of the vinegar solution?</h3>

The concentration of a solution is the amount of solute in a given volume of solution.

Concentration can be expressed as:

  • molar concentration
  • percentage concentration

The concentration of the vinegar solution is 4.76% (w/w). This means that 4.76 g of vinegar is present in 100 g of solution.

Mass of vinegar = 4.76 g

molar mass if vinegar = 60 g/mol

moles of vinegar = 4.76/60 = 0.0793 moles

volume of solution/water = 100 mL or 0.1 L

Molarity of vinegar = 0.0793/0.1 = 0.793 M

1 mole of vinegar reacts with 1 mole of NaOH

let the volume of vinegar required be V

0.793 M × V = 40 × 0.1

V = 4/0.793

V = 5.04 mL

Therefore, the volume of vinegar require is 5.04 mL.

Learn more about molarity at: brainly.com/question/26528084

4 0
3 years ago
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