Answer:
The answer is 12.67 TMU
Explanation:
Recall that,
worker’s eyes travel distance must be = 20 in.
The perpendicular distance from her eyes to the line of travel is =24 in
What is the MTM-1 normal time in TMUs that should be allowed for the eye travel element = ?
Now,
We solve for the given problem.
Eye travel is = 15.2 * T/D
=15.2 * 20 in/24 in
so,
= 12.67 TMU
Therefore, the MTM -1 of normal time that should be allowed for the eye travel element is = 12.67 TMU
Answer : 6.3 g/cm3
Step by step explanation:
Density = mass/volume
I would say D. because you round to the nearest whole number and 0.04 is way less than 0.5 which is a good rounding up number.
Ruff's image is 50m behind the mirror surface and the image is also 3m tall.
This is because it is a plane mirror.
