Answer:
29.39 kg
Explanation:
From the question,
W = mg...................... Equation 1
Where W = weight of the cuboid box, m = mass of the cuboid box, g = acceleration due to gravity.
make m the subject of the equation
m = W/g.................. Equation 2
Given: W = 288 N
Constant: g = 9.8 m/s²
Substitute these values into equation 2
m = 288/9.8
m = 29.39 kg
Answer:
The read will be 20.9[C]![x=\frac{(y-y_{1} )}{(y_{2} -y_{1} )}*(x_{2}-x_{1})+y_{1}\\ x=\frac{(18-0 )}{(95 -0 )}*(100-2)+2\\\\x= 20.9[C]](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B%28y-y_%7B1%7D%20%29%7D%7B%28y_%7B2%7D%20-y_%7B1%7D%20%29%7D%2A%28x_%7B2%7D-x_%7B1%7D%29%2By_%7B1%7D%5C%5C%20%20x%3D%5Cfrac%7B%2818-0%20%29%7D%7B%2895%20-0%20%29%7D%2A%28100-2%29%2B2%5C%5C%5C%5Cx%3D%2020.9%5BC%5D)
Explanation:
This is a problem related to linear interpolation, Linear interpolation consists of tracing a line through two known points y = r (x) and calculating the intermediate values according to this line.
The equation of a known line two points (x1, y1)and (x2, y2) = (2,0) (100,95) is:
![\frac{(y-y_{1} )}{(y_{2} -y_{1} )}=\frac{(x-y_{1} )}{(x_{2}-x_{1} )}](https://tex.z-dn.net/?f=%5Cfrac%7B%28y-y_%7B1%7D%20%29%7D%7B%28y_%7B2%7D%20-y_%7B1%7D%20%29%7D%3D%5Cfrac%7B%28x-y_%7B1%7D%20%29%7D%7B%28x_%7B2%7D-x_%7B1%7D%20%20%29%7D)
If we clear y from the equation we have:
[tex]y=\frac{(x-y_{1})}{(x_{2}-x_{1} )}*(y_{2} -y_{1} )+y_{1} \\replacing
Answer:
The speed will be "18km/s". A further explanation is given below.
Explanation:
According to the question, the values are:
Wavelength,
![\lambda = 656.46 \ nm](https://tex.z-dn.net/?f=%5Clambda%20%3D%20656.46%20%5C%20nm)
![\Delta \lambda = 0.04](https://tex.z-dn.net/?f=%5CDelta%20%5Clambda%20%3D%200.04)
![c=3\times 10^8](https://tex.z-dn.net/?f=c%3D3%5Ctimes%2010%5E8)
As we know,
⇒ ![\frac{\Delta \lambda}{\lambda} =\frac{v}{c}](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20%5Clambda%7D%7B%5Clambda%7D%20%3D%5Cfrac%7Bv%7D%7Bc%7D)
On substituting the values, we get
⇒ ![\frac{656.46}{0.04} =\frac{v}{3\times 10^8}](https://tex.z-dn.net/?f=%5Cfrac%7B656.46%7D%7B0.04%7D%20%3D%5Cfrac%7Bv%7D%7B3%5Ctimes%2010%5E8%7D)
⇒ ![v=\frac{656.46}{0.04} (3\times 10^8)](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B656.46%7D%7B0.04%7D%20%283%5Ctimes%2010%5E8%29)
⇒ ![=16411.5\times 3\times 10^8](https://tex.z-dn.net/?f=%3D16411.5%5Ctimes%203%5Ctimes%2010%5E8)
⇒ ![=18280 \ m/s](https://tex.z-dn.net/?f=%3D18280%20%5C%20m%2Fs)
or,
⇒ ![=18 \ km/s](https://tex.z-dn.net/?f=%3D18%20%5C%20km%2Fs)
Answer:
60/90
Explanation:
I think because the train's highest velocity is 60 n the time is 90