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Ghella [55]
3 years ago
10

Y’all wann trade in rob.lox I have a violet Valkyrie

Physics
2 answers:
Advocard [28]3 years ago
8 0

Answer:

No no no no no no no no no no no no no

romanna [79]3 years ago
8 0
Pay me, I want 600k by 2:00
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The operating temperature of a tungsten filament in an incandescent light bulb is 2450 K, and its emissivity is 0.350. Find the
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Answer:

The value is   A =  2.80 *10^{-4} \  m^2

Explanation:

From the question we are told that

The  operating temperature is  T  =  2450 \  K

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 The  power rating is  P  =  200 \  W

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      A = \frac{P}{ e *  \sigma  *  T^2}

Where  \sigma is the Stefan Boltzmann constant  with value  

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So

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